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umka21 [38]
3 years ago
14

Jack has twice as many dimes as quarters. If the total value of the coins is $6.30, how many dimes does he have?

Mathematics
1 answer:
ycow [4]3 years ago
4 0

Answer:

Number of dimes = 28

Step-by-step explanation:

Given that:

Worth of coins = $6.30 = 6.30 * 100 = 630 cents

Let,

x be the number of dimes

y be the number of quarters

According to given statement;

x = 2y    Eqn 1

10x+25y = 630    Eqn 2

Putting x = 2y in Eqn 2

10(2y) + 25y = 630

20y + 25y = 630

45y = 630

Dividing both sides by 45

\frac{45y}{45}=\frac{630}{45}\\y=14

Putting y=14 in Eqn 1

x = 2(14)

x = 28

Hence,

Number of dimes = 28

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Subtraction is a mathematical operation that reflects the removal of things from a collection. The number of bags that zips on them is 78.

<h3>What is subtraction?</h3>

Subtraction is a mathematical operation that reflects the removal of things from a collection. The negative symbol represents subtraction.

Given the number of bags that the company makes is 140. 39 of the bags have buttons but no zips. 21 of the bags have zips but no buttons. 23 of the bags have neither zips nor buttons.

Bags that have both zip and button

= Total number of bags - Number of bags with zips but no buttons - Number of bags with buttons but no zips - Number of bags with nor zips nor the buttons

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n = Bags that have both zip and button + Number of bags with zips but no buttons

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Hence, the number of bags that zips on them is 78.

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brainly.com/question/1927340

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Answers:

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==============================================================

Explanation:

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Check out the attached image. Using a red pen, I extended one of the lines to form a triangle. From the alternate interior angle theorem, we know that one of the angles of the triangle is 75 degrees (alternate interior angles are congruent). Again this stems from the fact that the lines are parallel.

I've also introduced the variable z to help find x. The angles x and z add up to 180 degrees since they form a straight line. So we need to find z before we can find x.

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