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umka21 [38]
3 years ago
14

Jack has twice as many dimes as quarters. If the total value of the coins is $6.30, how many dimes does he have?

Mathematics
1 answer:
ycow [4]3 years ago
4 0

Answer:

Number of dimes = 28

Step-by-step explanation:

Given that:

Worth of coins = $6.30 = 6.30 * 100 = 630 cents

Let,

x be the number of dimes

y be the number of quarters

According to given statement;

x = 2y    Eqn 1

10x+25y = 630    Eqn 2

Putting x = 2y in Eqn 2

10(2y) + 25y = 630

20y + 25y = 630

45y = 630

Dividing both sides by 45

\frac{45y}{45}=\frac{630}{45}\\y=14

Putting y=14 in Eqn 1

x = 2(14)

x = 28

Hence,

Number of dimes = 28

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Which point is part of the solution of the inequality y 2 12x – 11.
Papessa [141]

Answer:

Point (0,0)

Step-by-step explanation:

Given the inequality y > 12x – 11.

We will check which of the given options will be applied for the inequality

A) (1,0)

Substitute with x = 1 and y = 0

0 > 12*1 - 11

0 > 1   ⇒ Wrong

So, Point (1,0) is not part of the solution of the inequality.

B) (3,2)

Substitute with x = 3 and y = 2

2 > 12*3 - 11

0 > 25  ⇒ Wrong

So, Point (3,2) is not part of the solution of the inequality.

C) (1,1)

Substitute with x = 1 and y = 1

1 > 12*1 - 11

1 > 1   ⇒ Wrong

So, Point (1,1) is not part of the solution of the inequality.

D) (0,0)

Substitute with x = 1 and y = 0

0 > 12*0 - 11

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So, Point (0,0) is part of the solution of the inequality.

Also, see the attached figure which represents the given inequality

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3 years ago
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23

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