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ratelena [41]
2 years ago
15

(2x-7)-(4x^2+6x-3)+(x^2+4)

Mathematics
1 answer:
masha68 [24]2 years ago
8 0

Answer:

-3x^2-4x

Step-by-step explanation:

Simplify:

\left(2x-7\right)-\left(4x^2+6x-3\right)+\left(x^2+4\right)

=2x-7-\left(4x^2+6x-3\right)+x^2+4

Group same factor:

=-\left(4x^2+6x-3\right)+x^2+2x-7+4

Add :

=-\left(4x^2+6x-3\right)+x^2+2x-3

Apply the distributive law: -(a+b) = -a - b

-\left(4x^2+6x-3\right)=-4x^2-6x+3

=-4x^2-6x+3+x^2+2x-3

Group same factor:

=-4x^2+x^2-6x+2x+3-3

Subtract:

=-4x^2+x^2-6x+2x

Add:

=-3x^2-6x+2x

Group same factor:

=-3x^2-4x

Hence answer = -3x^2-4x

<u><em>~lenvy~</em></u>

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Step-by-step explanation:

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