Hey there mate ;),
Area of The shades region is <u>3098 m^2</u>
The solution is attached as picture. Please check.
<em>Answered</em><em> </em><em>by</em><em> </em><em>Benjemin</em>
Answer:
k=10
Step-by-step explanation:
g(x)=2x^2+ kx+18
when x=-2
g(-2)=2 (-2)^2 -2k +18
Since when x is -2, y =6
6=2 (-2)^2 -2k +18
6=18+8-2k
2k=26-6
2k=20
k=10
Answer:
W = 15/4 ft . ib
Step-by-step explanation:
Force = 10ib
According to hooked law, f(x) = kx
x = 4inches = 4/12 ft
x= 1/3ft
f(x) = 1/3k
10 = 1/3k
k = 30 ib/ft
f(x) = 30x
Workdone = integral of f(x) with its limit
6 inches = 6/12 ft
= 1/2ft
W = integral(1/2 to 0) of 30x
W = 15x^2(1/2 to 0)
W = 15(1/2)^2 - 15(0)^2
W = 15(1/4) - 0
W = 15/4 ft. Ib
Hey there! I'm happy to help!
First, let's find the area of the top of the bar.
30×70=2100
This is the same as the bottom of the bar, so we have another 2100 mm, giving us 4200 in total.
Now we want to find the two long sides. This is 70×4.5, which is 315. Since there are two of these sides, we have another 315, giving us 630 in total there.
Now we have the short sides.
30×4.5=135
135×2=270
Now, we add up all of these measurements.
4200+630+270=5100
Therefore, Will's Wrapping Company will need 5100 mm² of paper to make their wrapper.
Have a wonderful day! :D