Answer:
METHOD 1:
5x+7(x+1)=5x-21
5x+7x+7=5x-21
12x+7=5x-21
12x-5x=-21-7
7x=-28
x=28/7
x=4
METHOD 2:
5x+7(x+1)=5x-21
5x+7(x+1)=5x-21-5x
7(x+1)=-21
7x+7=-21
7x=-28
x=4
Step-by-step explanation:
METHOD 1:
5x+7(x+1)=5x-21
5x+7x+7=5x-21
12x+7=5x-21
12x-5x=-21-7
7x=-28
x=28/7
x=4
METHOD 2:
5x+7(x+1)=5x-21
5x+7(x+1)=5x-21-5x
7(x+1)=-21
7x+7=-21
7x=-28
x=4
Answer:
Option 3. 71 ft. is the distance between B and top of the hill.
Step-by-step explanation:
Let the height of the hill is h ft and the distance of A from the hill be x ft and distance from B to hill is y.
It is given distance between A and B is 45 ft. ∠BAO = 65° and ∠ABO = 80°.
We have to find the distance of B from the top of the hill.
Now from ΔACO 

From ΔBCO 
h = 5.67x
Now h = 5.67x = 2.14(45-x)
5.67x = 96.3 - 2.14x
2.14x + 5.67x = 96.3
7.81x = 96.3
x = 96.3/7.81 = 12.33 ft
Therefore 


Therefore 71 ft is the distance between B and the top of the hill.
Answer:
A y =
1
2
x − 6
Step-by-step explanation:
Answer:
X= $3.99
Step-by-step explanation:
X is the value of each book
Answer:

Step-by-step explanation:
To find
, we need to eliminate
in this system of equations:
(1)
(2)
From (1) and (2):


Then, we equalize both expressions and solve for
:



