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Free_Kalibri [48]
2 years ago
12

Anyone have the answer for this

Mathematics
2 answers:
pogonyaev2 years ago
8 0

\huge\bold{To\:find:}

✎ The length of the hypotenuse.

\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}

\sf\purple{The\:length\:of\:the\:hypotenuse \:"c"\:is\:5.10\:km.}

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

Using Pythagoras theorem, we have

( {perpendicular})^{2}  + ( {base})^{2}  = ( {hypotenuse})^{2} \\  ⇢ ( {5 \: km})^{2}  + ( {1 \: km})^{2}  = ( {c})^{2}  \\ ⇢ 25 \:  {km}^{2}  + 1  \: {km}^{2}  =  {c}^{2}  \\ ⇢ 26 \:  {km}^{2}  =  {c}^{2}  \\ ⇢  \sqrt{26 \:  {km}^{2}  }  = c \\ ⇢5.0990 \: km = c \\ ⇢5.10 \: km = c

\sf\blue{Therefore,\:the\:length\:of\:the\:hypotenuse\:is\:5.10\:km.}

\huge\bold{To\:verify :}

( {5 \: km})^{2}  + ( {1 \: km})^{2}  = ( {5.10 \: km})^{2}  \\ ⇝25 \:  {km}^{2}  + 1  \: {km}^{2}  = 26 \:  {km}^{2}  \\ ⇝26 \:  {km}^{2}   = 26\:  {km}^{2}  \\ ⇝L.H.S.=R. H. S

Hence verified.

\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘

scoray [572]2 years ago
5 0
The answer is radical 26. Since the triangle is right (given) you can use Pythagorean’s theorem (a^2+b^2=c^2) so in this case: c^2= 1+25=26 and you square root both sides to get rid of the ^2 and you get radical 26.
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