Part 1 : Adding & Subtracting Monomials

Mathematics

1 answer:

Anni [7]3 years ago

7 0

Answer:

1. 15a⁵b²+4a⁵b²

= 19a⁵b²

2. -7m-m²+4m²-3m

= -7m -3m -m²+4m²

= -10m +4m²

3. 2pq⁷ and -pq⁷

= (2pq⁷) +(-pq⁷)

= 2pq⁷-pq⁷

= pq⁷

4. -13xy from -5xy

= -5xy - 13xy

= - 18xy

it's your answer . check it out

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What is the sum of 1+2+.....+50?

Natasha_Volkova [10]

Answer:

sum is 1275

Step-by-step explanation:

$sum = \frac{n}{2} [2a + (n - 1)d] \\ \\ sum = \frac{50}{2} [(2 \times 1) + (50 - 1) \times 1] \\ \\ sum = 25(51) \\ sum = 1275$

7 0

3 years ago

Consider the integral 8 (x2+1) dx 0 (a) Estimate the area under the curve using a left-hand sum with n = 4. 250 Is this sum an o

Leya [2.2K]

Answer:

(a) 120 square units (underestimate)

(b) 248 square units

Step-by-step explanation:

(a) left sum

See the attachment for a diagram of the areas being summed (in orange). This is the sum of the first 4 table values for f(x), each multiplied by 2 (the width of the rectangle). Quite clearly, the curve is above the rectangle for the entire interval, so the rectangle area underestimates the area under the curve.

left sum = 2(1 + 5 + 17 + 37) = 2(60) = 120 . . . . square units

(b) right sum

The right sum is the sum of the last 4 table values for f(x), each multiplied by 2 (the width of the rectangle). This sum is ...

right sum = 2(5 +17 + 37 +65) = 2(124) = 248 . . . . square units