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krek1111 [17]
3 years ago
7

1. Add the polynomials. What is the coefficient of the 'x' term? * (2x² – 7x + 6) + (-3x² + 7x)

Mathematics
1 answer:
Alborosie3 years ago
5 0

Answer:

6−x to the 2

Step-by-step explanation:

(1): "x2"   was replaced by   "x^2".  1 more similar replacement(s).

STEP

1

:

Equation at the end of step 1

 (((2•(x2))-7x)+6)+((0-3x2)+7x)

STEP

2

:

Equation at the end of step

2

:

 ((2x2 -  7x) +  6) +  (7x - 3x2)

STEP

3

:

Trying to factor as a Difference of Squares

3.1      Factoring:  6-x2

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Given:

Consider the expression are

1) \sqrt{36}

2) \sqrt[3]{-8}

3) -\sqrt{100}

4) \sqrt[3]{27}

To find:

The simplified form of each expression.

Solution:

1. We have,

\sqrt{36}=\sqrt{6^2}

\sqrt{36}=6

Therefore, the value of this expression is 6.

2. We have,

\sqrt[3]{-8}=(-8)^{\frac{1}{3}}

\sqrt[3]{-8}=((-2)^3)^{\frac{1}{3}}

\sqrt[3]{-8}=(-2)^{\frac{3}{3}}

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Therefore, the value of this expression is -2.

3. We have,

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-\sqrt{100}=-10

Therefore, the value of this expression is -10.

4. We have,

\sqrt[3]{27}=(27)^{\frac{1}{3}}

\sqrt[3]{27}=(3^3)^{\frac{1}{3}}

\sqrt[3]{27}=(3)^{\frac{3}{3}}

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