38.=721.8 it's really just a matter of multiplication. I only have he answer for this one but, y'know, work and whatnot. If you would multiply 3 by 3 than wou would do the same for this problem
No. 1 = x
No. 2 = 2x+7
No. 3 = x-12
Answer:
x+(2x+7)+(x-12) = 131
From there you solve to get the numbers:
34, 75 and 22
We are given with
p2 + 2pq = 0.64
and another formula is
p2 + 2pq + q2 = 1
Substituting
0.64 + q2 = 1
q2 = 1 - 0.64
q2 = 0.36
q = 0.6
Another formula is
p + q = 1
p = 1 - 0.6
p = 0.4
What is asked is 2pq
p2 + 2pq = 0.64
2pq = 0.64 - 0.4^2
2pq = 0.48
There is 48% that has the heterozygous trait.
Answer:
Hence, the relation R is a reflexive, symmetric and transitive relation.
Given :
A be the set of all lines in the plane and R is a relation on set A.
To find :
Which type of relation R on set A.
Explanation :
A relation R on a set A is called reflexive relation if every 
then 
.
So, the relation R is a reflexive relation because a line always parallels to itself.
A relation R on a set A is called Symmetric relation if 
then 
for all 
.
So, the relation R is a symmetric relation because if a line 
is parallel to the line 
the always the line is parallel to the line .
A relation R on a set A is called transitive relation if and 
then 
for all 
.
So, the relation R is a transitive relation because if a line s parallel to the line and the line is parallel to the line 
then the always line is parallel to the line .
Therefore the relation R is a reflexive, symmetric and transitive relation.
(5x⁴ - 3x³ + 6x) - (3x³ + 11x² - 8x)<span>
</span>Expand the second bracket by multiplying throughout by -1
5x⁴ - 3x³ + 6x - <span>3x³ - 11x² + 8x
</span>
Group like terms and simplify
5x⁴ - 3x³ - 3x³ - 11x² + 6x <span>+ 8x
</span>5x⁴ <span>- 6x</span>³ - <span>11x² + 14x</span>
