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jek_recluse [69]
3 years ago
9

What would make this problem no solutions? fill in the blank.

Mathematics
1 answer:
lesya692 [45]3 years ago
8 0

Answer:

6

Step-by-step explanation:

the answer is six

I hope it helps

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Subtract the following polynomials, then place the answer in the proper location on the grid. Write the answer in descending pow
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12 a^2 + 60 a - 8
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3 0
3 years ago
PLEASE I NEED HELP INSTANTLY <br> I WILL GIVE BRAINLY AND THANKS
Goryan [66]

Answer:

so you're going to need to find the slope. in order to do that use (y2-y1)/(x2-x1)

(7-(-2))/(0-8)

simplify

9/-8

simplify -9/8

now using y=mx+b, we need to find b. so we can plug in the coordinates of (0,7) or (8,-2). let's use (8,-2) because it involves more math.  

y=mx+b

-2=(-9/8)(8)+b

multiply (-9/8) by 8 to get -9

-2=-9+b

add 9 to both sides

7=b

so our equation is now

y=-(9/8)x+7

Step-by-step explanation:

3 0
2 years ago
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What is 7x30=7x----tens
Pavlova-9 [17]
What is 7x30 = 7 x --- tens = --- tens = ---
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3 years ago
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RoseWind [281]

Answer:

m\angle KLM=53.13^o

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle KOM

In the triangle KOM

we have

KO=MO=r=5\ units

KM=8\ units

Applying the law of cosines

8^2=5^2+5^2-2(5)(5)cos(KOM)

64=50-50cos(KOM)

50cos(KOM)=50-64

50cos(KOM)=-14

cos(KOM)=-14/50

m\angle KOM=cos^{-1}(-14/50)

m\angle KOM=106.26^o

step 2

Find the measure of the arc KM

we know that

arc\ KM=m\angle KOM ----> by central angle

we have

m\angle KOM=106.26^o

so

arc\ KM=106.26^o

step 3

Find the measure of angle KLM

we know that

The inscribed angle is half that of the arc comprising  

m\angle KLM=\frac{1}{2}[arc\ KM]

we have

arc\ KM=106.26^o

substitute

m\angle KLM=\frac{1}{2}[106.26^o]

m\angle KLM=53.13^o

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I would like to help but, I need more background information.
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