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liraira [26]
3 years ago
6

What is the relationship between the average kinetic energy of the particles of a substance and the temperature of that substanc

e?
Physics
1 answer:
Genrish500 [490]3 years ago
4 0
Kinetic energy is the energy that an object has because of its motion. The molecules in a substance have a range of kinetic energies because they don't all move at thesame<span> speed. As a subtance absorbs heat the particles move faster so the average kinetic energy and therefore the temperature increases.

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the person is not able to see the far lying object clearly. which type of lens will the doctor prescribe him give reason?
ASHA 777 [7]

Answer:

correction of farsightedness uses a converging lenses that compensates for the under convergence by the eye. the converging lens produces an image farther from the eye than the object so that farsighted can see it clearly.

8 0
3 years ago
A 2.03 kg book is placed on a flat desk. Suppose the coefficient of static friction between the book and the desk is 0.602 and t
diamong [38]

Answer:

11.98 N

Explanation:

Normal force =   mg =  2.03 * 9.81

coeff of static friction must be overcome for the book to begin moving

       .602 = F / (2.03 * 9.81)   = 11.98  N

5 0
3 years ago
The fundamental force that is weak, long ranged and always relates the attraction of two masses is _____.
shutvik [7]

By definition this is the b) gravitational force.

5 0
3 years ago
Which statements about braking a car are true? A)The greater the kinetic energy of a car, the longer it takes for the car to sto
NikAS [45]

Answer:

option c  

Explanation:

Kinetic energy is due to the speed of a body.

K.E = \frac{1}{2}mv^2

When speed is doubled, the kinetic energy  is quadruple.

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3 0
3 years ago
Read 2 more answers
Suppose a 65 kg person stands at the edge of a 6.5 m diameter merry-go-round turntable that is mounted on frictionless bearings
Hatshy [7]

Answer:0.316 rad/s

Explanation:

Given

mass of Person m=65 kg

velocity of person v=3.8 m/s

diameter of turntable d=6.5 m

moment of Inertia of the table I_0=1850 kg-m^2

Moment of inertia of Person I

I=mr^2=65\times (\frac{6.5}{2})^2

I=686.56 kg-m^2

initial angular velocity \omega _1=\frac{v}{r}

\omega _1=\frac{3.8}{3.25}=1.17 rad/s

Conserving Angular momentum

I\omega _1=(I+I_0)\omega _2 , where \omega _2=final\ angular\ velocity

686.56\times 1.17=(686.56+1850)\times \omega _2

\omega _2=\frac{686.56}{2536.56}\times 1.17

\omega _2=0.316 rad/s

4 0
3 years ago
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