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2 years ago

6. To show how powerful he is, Mr. Avalos pushes on the wall with a force of 150 N for a whole minute!

Physics

1 answer:

Ede4ka [16]2 years ago

8 0

If the wall doesn't move, its mean that <u>the work he did is 0 J</u>.

<h3>Introduction</h3>

Hello my friend ! Here, I will help you. Alright, before it, I will to introduce to you about work (physics). In the world of physics, <u>work is the amount of force exerted to cause an object to move a certain distance from its starting point</u>. The amount of work will be proportional to the increase in force and increase in displacement. Amount of work can be calculated by this equation :

$\boxed{\sf{\bold{W = F \times s}}}$

With the following condition :

W = work (J)
F = force (N)
s = shift or displacement (m)

<h3>Proof</h3>

How about a stationary object like a wall pushed by Mr. Avalos ? Yes it is 0 J. Let's prove it!

Give :

F = force of Mr. Avalos = 150 N
s = displacement of wall = 0 m
t = interval of the time = 60 s

Asked : W = work = ... J

Proven :

$\sf{W = F \times s}$

$\sf{W = 150 \times 0}$

$\boxed{\sf{W = 0 \: J}}$ (Q.E.D)

Calculate the total energy of an object moving horizontally brainly.com/question/26485693

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3 years ago

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Complete question:

The exit nozzle in a jet engine receives air at 1200 K, 150 kPa with negligible kinetic energy. The exit pressure is 80 kPa, and the process is reversible and adiabatic. Use constant specific heat at 300 K to find the exit velocity.

Answer:

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Explanation:

Given;

initial temperature, T₁ = 1200K

initial pressure, P₁ = 150 kPa

final pressure, P₂ = 80 kPa

specific heat at 300 K, Cp = 1004 J/kgK

k = 1.4

Calculate final temperature;

$T_2 = T_1(\frac{P_2}{P_1})^{\frac{k-1 }{k}$

k = 1.4

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inlet velocity is negligible;

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3 years ago

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Answer:

If both the radius and frequency are doubled, then the tension is increased 8 times.

Explanation:

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$a_{r} = 4\pi^{2}\cdot f^{2}\cdot R$ (1)

Where:

$f$ - Frequency, measured in hertz.

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From Second Newton's Law, the centripetal acceleration is due to the existence of tension ( $T$ ), measured in newtons, through the string, then we derive the following model:

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By applying (1) in (2), we have the following formula:

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From where we conclude that tension is directly proportional to the radius and the square of frequency. Then, if radius and frequency are doubled, then the ratio between tensions is:

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$\frac{T_{2}}{T_{1}} = 4\cdot 2$

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2 years ago