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3 years ago

F(-5) = -5^2 - 1 simplified

Mathematics

2 answers:

serious [3.7K]3 years ago

8 0

Answer:3

Step-by-step explanation:

MA_775_DIABLO [31]3 years ago

3 0

Answer:

It equals 24

Step-by-step explanation:

Step 1- Multiply the power

f(-5)=25-1

Step 2- Subtract

f(-5)=24

Conclusion, it equals 24.

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Callie has a new kitten. They can weigh 3 pounds less than half the weight of Callie‘s cat. Together the cat and kitten weigh 18

gavmur [86]

Answer:

The weight of cat is 14 pounds and the weight of kitten is 4 pounds.

Step-by-step explanation:

Given:

Callie has a new kitten. It can weigh 3 pounds less than half the weight of Callie‘s cat. Together the cat and kitten weigh 18 pounds.

Now, to find the weight of each animal:

Let the cat's weight be $x.$

And the kitten weight = $\frac{x}{2} -3$

Total weight of cat and kitten = 18 pounds.

Now, to set an equation to get the weight of each animal:

$(x)+(\frac{x}{2}-3)=18$

$x+\frac{x}{2} -3=18$

$\frac{2x+x-6}{2} =18$

$\frac{3x-6}{2} =18$

Multiplying both sides by 2 we get:

$3x-6=36$

Adding both sides by 6 we get:

$3x=42$

Dividing both sides by 3 we get:

$x=14\ pounds.$

The weight of cat = 14 pounds.

Substituting the value of $x$ to get the kitten's weight:

$\frac{x}{2} -3\\\\=\frac{14}{2}-3\\\\=7-3\\\\=4.$

The kitten's weight = 4 pounds.

Therefore, the weight of cat is 14 pounds and the weight of kitten is 4 pounds.

7 0

3 years ago

F(x)=x²+4x-7 determine the vertex

asambeis [7]

Answer:

The vertex of this parabola is $(-2,-11)$

Step-by-step explanation:

One way of finding the x-coordinate of the vertex of a parabola is by using the equation $-\frac{b}{2a}$

From the function $f(x)=x^2+4x-7$ , we can see that

$a=1\\b=4\\c=-7$

This means that

$-\frac{b}{2a}=-\frac{4}{2(1)} =-2$

So, the x-value of the vertex is -2. Now, we can plug this x-value into the function to find the y-coordinate of the point.

$f(x)=x^2+4x-7\\\\f(-2)=(-2)^2+4(-2)-7\\\\f(-2)= 4-8-7\\\\f(-2)=-11$

Thus, the vertex of this parabola is $(-2,-11)$

3 0

3 years ago

The half-life of Radium-226 is 1590 years. If a sample contains 400 mg, how many mg will remain after 2000 years?

Assoli18 [71]

Answer:

167.27 mg.

Step-by-step explanation:

We have been given that the half-life of Radium-226 is 1590 years and a sample contains 400 mg.

We will use half life formula to solve our given problem.

$N(t)=N_0*(\frac{1}{2})^{\frac{t}{t/2}$ , where N(t)= Final amount after t years, $N_0$ = Original amount, t/2= half life in years.

Now let us substitute our given values in half-life formula.

$N(2000)=400*(\frac{1}{2})^{\frac{2000}{1590}$

$N(2000)=400*(0.5)^{1.2578616352201258}$

$N(2000)=400*0.4181633028874878239$

$N(2000)=167.26532115499512956\approx 167.27$

Therefore, the remaining amount of Radium-226 after 2000 years will be 167.27 mg.

3 0

3 years ago

the kline family went on vacation last year and paid $199 a night for the hotel room. This year, the price has increased by 5% .

dangina [55]

Answer: $208.95

Step-by-step explanation: $199 x .05= 9.95 + $199= $208.95

8 0

3 years ago

Pls help ASP I’ll give brainliest

Leokris [45]

Answer:

1620

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers