Please help, its for math, picture is attached with question

Urgent help!! Giving out extra points for explanations

ipn [44]

Answer:

A and b r the same but b is just under x line

C would be the answer cause if it was d it be under x line

8 0

3 years ago

In a one-tail test, the p-value is found to be equal to .068. If the test had been two-tail, the p-value would have been

devlian [24]

Answer:

The p-value for two-tailed test is 0.136

Step-by-step explanation:

Given;

one-tail test, p-value = 0.068,

In one-tailed test, we test for the possibility of a relationship in one direction and completely disregard the possibility of a relationship in the other direction.

One-tail test provides possibility of an outcome in one direction, while

two-tail test provides possibility of an outcome in two different directions.

Thus, the p-value for two-tailed test = 2 x 0.068 = 0.136

3 0

2 years ago

Hello help me with this question thanks in advance

AfilCa [17]

<h2>Question #22 Answer</h2>

B. 2 in.

<h3>Explanation:</h3>

$\frac{3\times4}{6}$

Cross out the common factor

$\frac{4}{2}\\ 2$

________________________________________________________

<h2>Question #23 Answer (Picture attached)</h2>

D. proportional, equal

<h3>Explanation:</h3>

$Two\ figure\ are\ sand\ to\ \\ be\ similar\ if\ the\\ Conesesponding\ sides\ we\\ proportional\ and\ the\\ Corresponding\ ongles\ are\\ equal.$

$If\ triangle\$ Δ $ABC\ is\ similar\ to$
Δ × $yz.\ Thes$
$\frac{AB}{xy}=\frac{AC}{xz}=\frac{BC}{yz}$

$and$

$< A= < X,\ < B= < y\ and\ < C= < z$

5 0

2 years ago

2 - ( - 4.51) = _____________

murzikaleks [220]

Your answer is, 6.51.

6 0

3 years ago

Read 2 more answers

A circle is growing so that the radius is increasing at the rate of 3 cm/min. How fast is the area of the circle changing at the

Naya [18.7K]

Answer:

The area is growing at a rate of $\frac{dA}{dt} =226.2 \,\frac{cm^2}{min}$

Step-by-step explanation:

<em>Notice that this problem requires the use of implicit differentiation in related rates (some some calculus concepts to be understood), and not all middle school students cover such.</em>

We identify that the info given on the increasing rate of the circle's radius is 3 $\frac{cm}{min}$ and we identify such as the following differential rate:

$\frac{dr}{dt} = 3\,\frac{cm}{min}$

Our unknown is the rate at which the area (A) of the circle is growing under these circumstances,that is, we need to find $\frac{dA}{dt}$ .

So we look into a formula for the area (A) of a circle in terms of its radius (r), so as to have a way of connecting both quantities (A and r):

$A=\pi\,r^2$

We now apply the derivative operator with respect to time ( $\frac{d}{dt}$ ) to this equation, and use chain rule as we find the quadratic form of the radius:

$\frac{d}{dt} [A=\pi\,r^2]\\\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}$

Now we replace the known values of the rate at which the radius is growing ( $\frac{dr}{dt} = 3\,\frac{cm}{min}$ ), and also the value of the radius (r = 12 cm) at which we need to find he specific rate of change for the area :

$\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}\\\frac{dA}{dt} =\pi\,*2*(12\,cm)*(3\,\frac{cm}{min}) \\\frac{dA}{dt} =226.19467 \,\frac{cm^2}{min}\\$

which we can round to one decimal place as:

$\frac{dA}{dt} =226.2 \,\frac{cm^2}{min}$

4 0

3 years ago