Answer:
FOR REGULAR PYRAMID with those dimension.
L.A = 96
FOR HEXAGONAL PYRAMID with those dimension
L.A = 171.71
Step-by-step explanation:
Please the question asked for L.A of a REGULAR PYRAMID, but the figure is a HEXAGON PYRAMID.
Hence I solved for both:
FOR REGULAR PYRAMID
Lateral Area (L.A) = 1/2* p * l
Where p = Perimeter of base
P = 4s
P = 4 * 6
P = 24cm
l = slanted height
l = 8cm
L.A = 1/2 * 24 * 8
L.A = 1/2 ( 192)
L.A = 96cm ^ 2
FOR AN HEXAGONAL PYRAMID
Lateral Area = 3a √ h^2 + (3a^2) / 4
Where:
a = Base Edge = 6
h = Height = 8
L.A = 3*6 √ 8^2 + ( 3*6^2) / 4
L.A = 18 √ 64 + ( 3 * 36) / 4
L.A = 18 √ 64 + 108/4
L.A = 18 √ 64+27
L.A = 18 √ 91
L.A = 18 * 9.539
L.A = 171.71
We normally think of 3x7, but the "7" is one more than 2 widths ... double the 3 and halve the 7 ==> 6 by 3.5 works ...
If he grew 12 flowers with 3 seed packets then there should be 4 seeds in one packet > 3 x 4 = 12
Devin needs 5 seed packets to have a total of 20 flowers in his garden
> 4 x 5 = 20
Step-by-step explanation:
f ( - 4) = 3 ( - 4) ² - 2( - 4)
=. 3 ( 16) + 8
=. 48 + 8 = 56
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