The answer is 25 % hope it helps
Answer:

Step-by-step explanation:
we are given half-life of PO-210 and the initial mass
we want to figure out the remaining mass <u>after</u><u> </u><u>4</u><u>2</u><u>0</u><u> </u><u>days</u><u> </u>
in order to solve so we can consider the half-life formula given by

where:
- f(t) is the remaining quantity of a substance after time t has elapsed.
- a is the initial quantity of this substance.
- T is the half-life
since it halves every 140 days our T is 140 and t is 420. as the initial mass of the sample is 5 our a is 5
thus substitute:

reduce fraction:

By using calculator we acquire:

hence, the remaining sample after 420 days is 0.625 kg
Answer: ok fine
Step-by-step explanation:
Hello :
PA = PB or PA² = PB²
(5-b)²+(4-2)² = (2-b)² + (5-2)²
(5-b)²+4 = (2-b)² + 9
25 -10b +b² + 4 = 4 -4b+b² +9
-6b = -16
b = 8/3
Answer:
1,900 square feet; f(3) represents the total number of square feet the construction crew has paved after 3 hours.
The function of the construction crew is an illustration of a linear function
The value of f(3) is 1900, and f(3) represents the total number of square feet paved after working for 3 hours
The function is given as:
To calculate f(3), we substitute 3 for x
Multiply 300 and 3
Add 900 and 1000
This means that the value of f(3) is 1900.
And it represents the total number of square feet paved after working for 3 hours
1,900 square feet; f(3) represents the total number of square feet the construction crew has paved after 3 hours.