Answer:
A = 222 units^2
Step-by-step explanation:
To find the area of this trapezoid, first draw an imaginary horizontal line parallel to AD and connecting C with AB (Call this point E). Below this line we have the triangle CEB with hypotenuse 13 units and vertical side (21 - 16) units, or 5 units. Then the width of the entire figure shown can be obtainied using the Pythagorean Theorem:
(5 units)^2 + CE^2 = (13 units)^2, or 25 + CE^2 = 169. Solving this for CE, we get |CE| = 12.
The area of this trapezoid is
A = (average vertical length)(width), which here is:
(21 + 16) units
A = --------------------- * (12 units), which simplifies to:
2
A = (37/2 units)(12 units) = A = 37*6 units = A = 222 units^2
We can see that the 33 degrees corresponds to angle A (parallel lines) meaning they’re equal.
This means that 33 + 2x = 5x (5x is the exterior angle, so the other two interior angles’ sum must equal to it)
3x = 33
x = 11
Answer:
Examination of the equation shows (graph):
x = 0, y = .5
Then .5 = c gives us the value of c giving
y = m x + .5 is our equation
Using y = 0, x = -1 gives
o = -1 * m + .5
m = .5
y = .5 x + .5 for the final equation
Check:
At x = 5, y = 3
3 = .5 (5) + .5 = 3
Answer:
Answers in the pics
Step-by-step explanation:
If you have any questions about the way I solved it, don't hesitate to ask ÷)
