Question

the perimeter of a childs rectangular sandbox is 18 feet if the length of the sandbox is one foot longer than the width write an equation that can find the length and width of the sandbox

Answer 1

Answer:

Equation:

$2(x+(x+1))=18$

Width = 4 feet

Length = 5 feet

Step-by-step explanation:

Let x feet be the width of the rectangle.

If the length of the sandbox is one foot longer than the width, then the length is x + 1 feet.

Use formula

$\text{Perimeter}=2(\text{Width}+\text{Length})$

The perimeter of a childs rectangular sandbox is 18 feet, thus

$18=2(x+(x+1))\\ \\18=2(x+x+1)\\ \\18=2(2x+1)\\ \\9=2x+1\ [\text{Divided by 2}]\\ \\2x+1-1=9-1\\ \\2x=8\\ \\x=4\ feet \\ \\x+1=5 \ feet$