All the angles created by the transversal intersecting through a pair of parallel lines have got many names and connections with each other, like Alternate Angles, Corresponding angles, consecutive interior angles etc.
As per the question statement, We are given a pair of parallel lines which is cut by a transversal. We are supposed to mark the following angles.
Alternate Interior Angles, Alternate Exterior Angles, Corresponding Angles and Consecutive Interior Angles.
Here is an attached image of the same with angles marked on it.
Alternate Interior Angles: ∠
= ∠
and ∠
=∠
Alternate Exterior Angles: ∠
=∠
and ∠
=∠
Corresponding Angles: ∠=∠ , ∠=∠ , ∠=∠ and ∠=∠
Consecutive Interior Angles: ∠=∠ and ∠=∠
- Parallel Lines: Parallel lines are those straight lines that are, no matter how far they are extended, always the same distance apart from one another.
- Transversal Line: In geometry, a transversal line intersects two lines in the same plane at two different locations.
To learn more about Transversal Line click on the link given below:
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I believe that b.Fractions are rational numbers is not true
sorry if its wrong
We have an arithmetic sequence with
<span>a0 = 1st 3-digit number divisible by 13 </span>
<span>a0 = 104 </span>
<span>d = 13 (why?) </span>
<span>last term is largest divisible by 13 = 988 </span>
<span>how many terms? (988-104)/13 + 1 = 69 </span>
<span>S = 69/2(104+988) = 37674</span>
Answer: 6.4 In decimal form. 32/5 in fraction form.
Step-by-step explanation:
So first times 8 by 12 which is 96
then, 3 times 5 which is 15
Simplify to 32/5
Answer:
- no question content
- (x, y) = (1/2, 4)
- (x, y) = (2, 10)
Step-by-step explanation:
1. No link, no question
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2. Divide the first equation by 2 and substitute for y using the expression in the second equation.
2x +(4x+2) = 5
6x = 3 . . . . . . . . . subtract 2
x = 3/6 = 1/2 . . . . divide by2
y = 4(1/2) +2 = 4 . . . . substitute into the equation for y
The solution is (x, y) = (1/2, 4).
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3. The solution using a graphing calculator is (x, y) = (2, 10). (see attached)
