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antiseptic1488 [7]
2 years ago
6

Is my Answers Correct? Very easy Question!

Mathematics
2 answers:
Aliun [14]2 years ago
7 0

Answer:

Step-by-step explanation:

Correct

zloy xaker [14]2 years ago
7 0

Step-by-step explanation:

the 5th one on the right is standard form,

the second one is perfect square form.

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I would like to request help for this problem. I am having trouble understand how to solve the problem.
VashaNatasha [74]

Answer:

The answer would be C.

Step-by-step explanationIt is C.!!!!!

6 0
3 years ago
Which graph shows the solution set for -5/2 x - 3_< 2?​
nikitadnepr [17]
The answer is the 3rd graph
8 0
2 years ago
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The length of a rectangular pool is 50 yards, and the width of the pool is 16 yards. What is the approximate length of the diago
melisa1 [442]

Answer:

52.5

Step-by-step explanation:

You would use the Pythagorean theorem to solve this. Using the formula,

a^2 + b^2 = ^2

You would have an equation of 50^2 + 16^2 = c ^2.

50^2 is 2500, and 16^2 is 256.

There, you have 2500+256 = c^2

add those together, and you have 2756.

Now, you have to find the square root of 2756 (to solve 2756 = c^2)

which leaves you with 52.4976189936 . Rounded to the nearest tenth, you end up with 52.5.

4 0
3 years ago
To keep producing a specific shirt style, a clothing company must make a profit of at least $5,000 on the style.
3241004551 [841]

Answer:

At x = 15 ; price meets profit goal

At x = 25 ; price does not meet profit goal

Step-by-step explanation:

Constraint:

p < -15x2 + 600x + 60

P ≥ 5,000

x = shirt price ;

If x = 15

p ≤ -15(15²) + 600(15) + 60

p ≤ -3375 + 9000 + 60

p ≤ 5685

p ≥ 5000

5685 ≥ 5000 ( condition is met)

2.)

With a shirt price of $25

x = 25

p ≤ -25(25²) + 600(25) + 60

p ≤ -15625 + 15000 + 60

p ≤ - 565

p ≥ 5000

-565 < 5000 ( condition is not met)

3 0
3 years ago
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100 POINTS URGENT PLEASE HELP
8090 [49]

<u>Domain</u><u>~</u><u> </u>

0 \leqslant b \leqslant 300

<u>Range</u><u>~</u><u> </u>

<u>0 \leqslant p \leqslant 225</u>

<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>:</em><em>)</em>

4 0
3 years ago
Read 2 more answers
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