a. Let 
be a random variable representing the weight of a ball bearing selected at random. We're told that 
, so
where 
. This probability is approximately
b. Let 
be a random variable representing the weight of the 
-th ball that is selected, and let 
be the mean of these 4 weights,
The sum of normally distributed random variables is a random variable that also follows a normal distribution,
so that
Then
c. Same as (b).
As far as I understand A)
This would only be a double bracket...
but you do
(4x+6) (x-3)
F 4x * X = 4xsquared
O 4x* -3 = -12x
I. 6xX = 6x
L. 6*-3 = -18
collect like terms:
answer= 4x2 - 6x -18
the 4x is squared :)
Answer:
y = x - 4
General Formulas and Concepts:
<u>Algebra I</u>
Slope-Intercept Form: y = mx + b
- m - slope
- b - y-intercept
Step-by-step explanation:
<u>Step 1: Define</u>
Slope <em>m</em> = 1
y-intercept <em>b</em> = -4
<u>Step 2: Write function</u>
y = x - 4
We have two questions, but we need to find the volume of the spherical tank first.
So the formula we will use to find the volume is:
(4/3)πr³=V
Let's fill in the information we have and solve. We will be using 3.14 for pi.
(4/3)(3.14)6³
(4/3)(3.14)(216)
4.1867×216
I'll be using the repeating decimal for 4.1867, I rounded to 7, but there is a repeating 6.
904.32
So the volume is 904.32 yards³ (or 904.78 if using the full pi)
We have to multiply the volume by 7.15.
904.32×7.15
6,465.89
It will cost $6,465.89 to fill the tank with the liquid.
