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2 years ago

Give some examples of quantities that increase or decrease at a constant rate expressed as a percent.

Mathematics

2 answers:

docker41 [41]2 years ago

7 0

I would help but I'm not sure what you are asking for us to do

VLD [36.1K]2 years ago

4 0

Answer:

Some things that experience exponential growth or decay, at a constant rate expressed as a percent, are: Populations of cities, rural areas, and animal populations, country or individuals wealth vs debt, trees and other plants growing over time, cities expanding, and industries (such as the movie rental agency) growing then dying

Step-by-step explanation:

i have no idea what this lesson is about but just got 100% on this journal so here!

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What is the value of x? PLEASE HELP

Natali5045456 [20]

Answer:

Step-by-step explanation:

5 0

2 years ago

Which relations are functions? List the relation number(s) that are function(s) in the answer bank

Sergeu [11.5K]

Answer:

options 1,3,4 are functions.

Step-by-step explanation:

RULE: a relation is said to be a function if every element in the domain ( the numbers in the left side in the below sets) is related to only one number ( number on the right side in the below sets).

Let us check each option one by one:

1. 3 2

9 1

-4 7

0 -2

here each number on the left side is mapped to or is related to one number only.

so this relation is a function

2. 7 1

-5 2,3

1 0

here, "-5" is mapped to two different numbers. so this relation is not a function.

3. -2 -4

2 4

6 8

-6 -8

here each number on the left side is mapped to or is related to one number only.

so this relation is a function

4. 1 3

-1 3

2 3

-2 3

here each number on the left side is mapped to or is related to one number only.

so this relation is a function.

even if it is related to the same number, it doesn't matter.

it should follow the above given rule that's it.

6 0

3 years ago

kogti [31]

Answer:

Step-by-step explanation:

$no \: of \: girls = \frac{4}{5 + 4} \times 36 \\ \\ = \frac{4}{9} \times 36 \\ \\ = 4 \times 4 \\ \\ = 16$

6 0

2 years ago

Read 2 more answers

Show your work.

Doss [256]

Answer:

1= 2,400 feet

2= 154 meters

3= 120 pints

4= 2. 056 centigrams

5= 16.1 C

6= 50F

7= -2.8C

1= multiply the length value by 3

2= divide the length value by 10

3= multiply the volume value by 8

4= divide the mass value by 10

5= Take the °F temperature and subtract 32. Multiply this number by 5. Divide this number by 9 to obtain your answer in °C.

6= multiply the temperature in degrees Celsius by 2, and then add 30 to get the (estimated) temperature in degrees Fahrenheit.

6 0

2 years ago

Read 2 more answers

A young couple purchases their first new home in 2011 for $95,000. They sell it to move into a bigger home in 2018 for $105,00

mart [117]

Given:

The value of home in 2011 is $95,000.

The value of home in 2018 is $105,000.

To find:

The exponential model for the value of the home.

Solution:

The general exponential model is

$y=ab^x$ ...(i)

where, a is initial value and b is growth factor.

Let 2011 is initial year and x be the number of years after 2011.

So, initial value of home is 95,000, i.e., a=95,000.

Put a=95000 in (i).

$y=95000b^x$ ...(ii)

The value of home in 2018 is $105,000. It means the value of y is 105000 at x=7.

$105000=95000b^7$

$\dfrac{105000}{95000}=b^7$

$\dfrac{21}{19}=b^7$

Taking 7th root on both sides, we get

$\left(\dfrac{21}{19}\right)^{\frac{1}{7}}=b$

Put $b=\left(\dfrac{21}{19}\right)^{\frac{1}{7}}$ in (ii).

$y=95000\left(\left(\dfrac{21}{19}\right)^{\frac{1}{7}}\right)^x$

$y=95000\left(\dfrac{21}{19}\right)^{\frac{x}{7}}$

Therefore, the required exponential model for the value of home is $y=95000\left(\dfrac{21}{19}\right)^{\frac{x}{7}}$ , where x is the number of years after 2011.

5 0

2 years ago