Answer:
1 39/50 hours. This is equivalent to 1.78 hours.
Step-by-step explanation:
The sum of the hours of work and the hours for break gives the work day hour which has been given as 8 hours.
Furthermore, given that the break time is 22 1/4%, the number of hours for break
= 22 1/4% × 8 hours
= 89/400 × 8
= 1 39/50 hours
The slope intercept form y=2x^2-x-13. Hope this helps :)
Answer:
Step-by-step explanation:
There is a specific order to do these kind of problems..
first, we do everything in parenthesis...
(9 + 8) + 6/3 - 7 * 2
17 + 6/3 - 7 * 2
now, starting from the LEFT side, do all multiplication and division in the order it comes
17 + 2 - 14
now, starting from the LEFT side, do all addition and subtraction in the order it comes
19 - 14 = 4
so ur answer is 4
Learn this...order of operations....this is the order u do these problems in..
PEMDAS
P = parenthesis
E = exponents
M = multiplication
D = division
A = addition
S = subtraction
keep in mind, multiplication/division are done from left to right....u do not have to do multiplication before u do division....it just depends on which comes first when starting from the left side.....that also applies to addition/subtraction
Answer:
7
4
Step-by-step explanation:
The <u>actual values</u> are shown on the given graph as <u>blue points</u>.
The <u>line of regression</u> is shown on the given graph as the <u>red line</u>.
From inspection of the graph, in the year 2000 the actual rainfall was 43 cm, shown by point (2000, 43). It appears that the regression line is at y = 50 when x is the year 2000.
⇒ Difference = 50 - 43 = 7 cm
<u>In 2000, the actual rainfall was </u><u>7</u><u> centimeters below what the model predicts</u>.
From inspection of the graph, in the year 2003 the actual rainfall was 44 cm, shown by point (2003, 40). It appears that the regression line is at y = 40 when x is the year 2003.
⇒ Difference = 44 - 40 = 4 cm
<u>In 2003, the actual rainfall was </u><u>4</u><u> centimeters above what the model predicts.</u>
