Answer:
Step-by-step explanation:
Given infinite system of linear equations is ax + by = 0
when (a,b) moves along unit circle in plane.
a) system having unique system (0, 0)
Since two of equation in thus system will be
![1.x+0.y=0\\x=0](https://tex.z-dn.net/?f=1.x%2B0.y%3D0%5C%5Cx%3D0)
and
![0.x+1.y=0\\y=0](https://tex.z-dn.net/?f=0.x%2B1.y%3D0%5C%5Cy%3D0)
It is clear that x = 0, y= 0 is the only solution
b) Linear independent solution in this system gives some set of solutions
![1.x+0.y=0\\\x=0](https://tex.z-dn.net/?f=1.x%2B0.y%3D0%5C%5C%5Cx%3D0)
and
![0.x+1.y=0\\y=0](https://tex.z-dn.net/?f=0.x%2B1.y%3D0%5C%5Cy%3D0)
Vector form is
![\left[\begin{array}{ccc}1&0\\0&1\end{array}\right] =I](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D%20%3DI)
c) for this equation if add 0x +0y = 0 to system , Nothing will change
Because [0,0] satisfies that equation
d) If one of the equation is ax + by = 0.00001
where 0.00001 is small positive number
so, the system will be inconsistent
Therefore, the system will have no solution.