QUAL A ÁREA, EM CENTÍMETROS QUADRADOS, DA FIGURA AO LADO?

Mathematics

1 answer:

Ratling [72]3 years ago

3 0

Answer:

Step-by-step explanation:

Dado:

Considere o quadrilátero como trapézio, então nós temos

soma dos lados paralelos = 13+22

altura = 12

Encontrar:

área de trapézio = ?

Solução:

Considere o quadrilátero como trapézio, então nós temos

$\textrm{área de trapézio}=\frac{1}{2}\times \textrm{soma dos lados paralelos}\times altura\\=\frac{1}{2}\times (13+22)\times 12\\=210\ centímetros quadrados$

You might be interested in

What is 41/6 simplified into 12

FrozenT [24]

41/6 = - 41/6 = - 6 5/6 = - 6.833333333333; Result written as a negative improper fraction, a mixed number (also called a mixed fraction) and a decimal number. Ordinary (simple, common) math fraction reducing to lowest terms (simplifying), answer with explanations below.

3 0

3 years ago

Read 2 more answers

30 movies were rented by 5 people. This is the same ratio as 3 people renting ___ movies.

fomenos

3 people rent 18 movies altogether. I person would rent 6 movies

6 0

3 years ago

Read 2 more answers

A cinema has three screens last Saturday there were 500 visitors 40% went to screen 1 ,25% went to screen 2 the rest went to scr

ratelena [41]

Answer:

200 visitors went to screen 1.

125 visitors went to screen 2.

175 visitors went to screen 3.

Step-by-step explanation:

We will find number of visitors who went to screen 1 by finding 40% of 500 as we are told that 40% of 500 visitors went to screen 1.

$500*\frac{40}{100} =5*40=200$

Therefore, 200 visitors went to screen 1.

Now we will find number of visitors who went to screen 2. We are told that 25% of 500 visitors went to screen 2.

$500*\frac{25}{100} =5*25=125$

Therefore, 125 visitors went to screen 2.

Now we will find the number of visitors who went to screen 3 by subtracting combined number of visitors who went to screen 1 and screen 2 from total number of visitors.

$500-(200+125)$