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Natalija [7]
3 years ago
8

QUAL A ÁREA, EM CENTÍMETROS QUADRADOS, DA FIGURA AO LADO?

Mathematics
1 answer:
Ratling [72]3 years ago
3 0

Answer:

Step-by-step explanation:

Dado:

Considere o quadrilátero como trapézio, então nós temos

soma dos lados paralelos = 13+22

altura = 12

Encontrar:

área de trapézio = ?

Solução:

Considere o quadrilátero como trapézio, então nós temos

\textrm{área de trapézio}=\frac{1}{2}\times \textrm{soma dos lados paralelos}\times altura\\=\frac{1}{2}\times (13+22)\times 12\\=210\ centímetros quadrados

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How much should Tabatha budget monthly for insurance that costs $956.89 for the entire year?
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Suppose a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%. A cell phon
leva [86]

Answer:

We conclude that the actual percentage of households is equal to 30%.

Step-by-step explanation:

We are given that a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%.

Their marketing people survey 150 households with the result that 43 of the households have three cell phones.

Let p = <u><em>proportion of households that have three cell phones NOT known.</em></u>

So, Null Hypothesis, H_0 : p = 30%      {means that the actual percentage of households is equal to 30%}

Alternate Hypothesis, H_A : p \neq 30%     {means that the actual percentage of households different from 30%}

The test statistics that would be used here <u>One-sample z-test for proportions;</u>

                                T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of households having three cell phones = \frac{43}{150} = 0.29

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So, <u><em>the test statistics</em></u>  =  \frac{0.29-0.30}{\sqrt{\frac{0.30(1-0.30)}{150} } }  

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<u>Now, at 1% significance level the z table gives critical value of -2.58 and 2.58 for two-tailed test.</u>

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <em><u>we fail to reject our null hypothesis</u></em>.

Therefore, we conclude that the actual percentage of households is equal to 30%.

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