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user100 [1]
2 years ago
7

Place each job in order from highest to lowest by reading each description. Think about other civiliation

Mathematics
1 answer:
anygoal [31]2 years ago
6 0

Answer:

1. Priests and rulers of society.

2. Warriors

3. Merchants

4. Blacksmiths

Step-by-step explanation:

1. They were born into status and religion was a big part of society so priests would be treated well.

2. Warriors were able to work their way up in society and became respectable.

3. These were lower level people right  under warriors and didnt lead a bad life.

4. Rejects and weren't able to have rights

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Please guys say me all answer correctly​
Ratling [72]

Answer:

9222521251

Step-by-step explanation:

+6261113051+

151232065+3

156

3 0
3 years ago
What is the mean (average) of these five numbers?
IRINA_888 [86]

Answer:

C. 5

Step-by-step explanation:

Mean: Numbers over amount of numbers

(2 + 4 + 5 + 6 + 8)/5

25/5

5

4 0
2 years ago
Why is the answer to this integral's denominator have 1+pi^2
ss7ja [257]

It comes from integrating by parts twice. Let

I = \displaystyle \int e^n \sin(\pi n) \, dn

Recall the IBP formula,

\displaystyle \int u \, dv = uv - \int v \, du

Let

u = \sin(\pi n) \implies du = \pi \cos(\pi n) \, dn

dv = e^n \, dn \implies v = e^n

Then

\displaystyle I = e^n \sin(\pi n) - \pi \int e^n \cos(\pi n) \, dn

Apply IBP once more, with

u = \cos(\pi n) \implies du = -\pi \sin(\pi n) \, dn

dv = e^n \, dn \implies v = e^n

Notice that the ∫ v du term contains the original integral, so that

\displaystyle I = e^n \sin(\pi n) - \pi \left(e^n \cos(\pi n) + \pi \int e^n \sin(\pi n) \, dn\right)

\displaystyle I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n - \pi^2 I

\displaystyle (1 + \pi^2) I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n

\implies \displaystyle I = \frac{\left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n}{1+\pi^2} + C

6 0
2 years ago
Simplify 16m6-15mn+m6+17mn​
tia_tia [17]

Answer:

17m^6 + 2mn

Step-by-step explanation:

16m^6 -15mn +m^6 + 17mn

Combine like terms, rewrite the equation and perform the operations between the coefficients,

16m^6 +m^6 -15mn+17mn

17m^6 + 2mn

3 0
2 years ago
Read 2 more answers
Evaluate Integral: 2sin(2x) from 0, pi/2
Neko [114]
Integral of 2sin(2x) is -cos(2x)
from 0 to pi/2 (sub pi/2 minus sub 0 for x) and then solve
= -cos(2*pi/2)-(-cos0)
= -cos pi + cos 0
= 1 + 1
= 2 
8 0
2 years ago
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