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2 years ago

Place each job in order from highest to lowest by reading each description. Think about other civiliation

Mathematics

1 answer:

anygoal [31]2 years ago

6 0

Answer:

1. Priests and rulers of society.

2. Warriors

3. Merchants

4. Blacksmiths

Step-by-step explanation:

1. They were born into status and religion was a big part of society so priests would be treated well.

2. Warriors were able to work their way up in society and became respectable.

3. These were lower level people right under warriors and didnt lead a bad life.

4. Rejects and weren't able to have rights

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Please guys say me all answer correctly

Ratling [72]

Answer:

9222521251

Step-by-step explanation:

+6261113051+

151232065+3

156

3 0

3 years ago

What is the mean (average) of these five numbers?

IRINA_888 [86]

Answer:

C. 5

Step-by-step explanation:

Mean: Numbers over amount of numbers

(2 + 4 + 5 + 6 + 8)/5

25/5

4 0

2 years ago

Why is the answer to this integral's denominator have 1+pi^2

ss7ja [257]

It comes from integrating by parts twice. Let

$I = \displaystyle \int e^n \sin(\pi n) \, dn$

Recall the IBP formula,

$\displaystyle \int u \, dv = uv - \int v \, du$

Let

$u = \sin(\pi n) \implies du = \pi \cos(\pi n) \, dn$

$dv = e^n \, dn \implies v = e^n$

Then

$\displaystyle I = e^n \sin(\pi n) - \pi \int e^n \cos(\pi n) \, dn$

Apply IBP once more, with

$u = \cos(\pi n) \implies du = -\pi \sin(\pi n) \, dn$

$dv = e^n \, dn \implies v = e^n$

Notice that the ∫ v du term contains the original integral, so that

$\displaystyle I = e^n \sin(\pi n) - \pi \left(e^n \cos(\pi n) + \pi \int e^n \sin(\pi n) \, dn\right)$

$\displaystyle I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n - \pi^2 I$

$\displaystyle (1 + \pi^2) I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n$

$\implies \displaystyle I = \frac{\left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n}{1+\pi^2} + C$

6 0

2 years ago

Simplify 16m6-15mn+m6+17mn

tia_tia [17]

Answer:

$17m^6 + 2mn$

Step-by-step explanation:

$16m^6 -15mn +m^6 + 17mn$

Combine like terms, rewrite the equation and perform the operations between the coefficients,

$16m^6 +m^6 -15mn+17mn$

$17m^6 + 2mn$

3 0

2 years ago

Read 2 more answers

Evaluate Integral: 2sin(2x) from 0, pi/2

Neko [114]

Integral of 2sin(2x) is -cos(2x)
from 0 to pi/2 (sub pi/2 minus sub 0 for x) and then solve
= -cos(2*pi/2)-(-cos0)
= -cos pi + cos 0
= 1 + 1
= 2

8 0

2 years ago