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Jet001 [13]
3 years ago
14

Let f(x)=x^2+2 and g(x)=1−3x. Find each function value: (f+g)(−1)

Mathematics
1 answer:
kykrilka [37]3 years ago
5 0

Answer:

it's 1+2+1+3 = 7 ......

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pantera1 [17]
D, let me know if you need explanationn <33333
8 0
3 years ago
A newsletter publisher believes that above 41A% of their readers own a personal computer. Is there sufficient evidence at the 0.
klemol [59]

Complete Question

A newsletter publisher believes that above 41% of their readers own a personal computer. Is there sufficient evidence at the 0.10 level to substantiate the publisher's claim?

State the null and alternative hypotheses for the above scenario.

Answer:

The null hypothesis is  H_o  : p \le   0.411

The  alternative hypothesis  is  H_a : \mu >  0.41

Step-by-step explanation:

From the question we are told that

   The  proportion is  p  =  0.41

Generally the null hypothesis is  H_o  : p \le   0.411

The  above condition represents the  null hypothesis because it contains and equality in its condition

  The  alternative hypothesis  is  H_a : \mu >  0.41

6 0
3 years ago
a pitcher contains 2 3/4 pints of orange juice. After you pour 5/8 of a pint into a glass, how much is left in the pitcher
olga nikolaevna [1]
17/8 = 2 1/8 U need to covert 2 3/4 to an improper fraction then covert it to 8ths which means you multiply the numerator and denominator by 2 and solve then simplify. :)
3 0
3 years ago
The range of y = - 32x ^ 2 + 90x + 3
mariarad [96]

Given:

The given function is:

y=-32x^2+90x+3

To find:

The range of the given function.

Solution:

We have,

y=-32x^2+90x+3

It is a quadratic function because the highest power of the variable x is 2.

Here, the leading coefficient is -32 which is negative. So, the graph of the given function is a downward parabola.

If a quadratic function is f(x)=ax^2+bx+c, then the vertex of the quadratic function is:

Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)

In the given function, a=-32,b=90,c=3.

\dfrac{-b}{2a}=\dfrac{-90}{2(-32)}

\dfrac{-b}{2a}=\dfrac{-90}{-64}

\dfrac{-b}{2a}=\dfrac{45}{32}

The value of the given function at x=\dfrac{45}{32} is:

y=-32(\dfrac{45}{32})^2+90(\dfrac{45}{32})+3

y=\dfrac{2121}{32}

The vertex of the given downward parabola is \left(\dfrac{45}{32},\dfrac{2121}{32}\right). It means the maximum value of the function is y=\dfrac{2121}{32}. So,

Range=\left\{y|y\leq \dfrac{2121}{32}\right\}

Range=\left(-\infty, \dfrac{2121}{32}\right ]

Therefore, the range of the given function is \left (-\infty, \dfrac{2121}{32}\right ].

8 0
3 years ago
Solve for a. ​ 1/3(21−3a)=6−a​ a.−1 b.0 c.no solution d.all real numbers
kifflom [539]
1/3(21 - 3a) = 6 - a
7 - a = 6 - a
7 = 6

Therefore, the equation has no solution.
3 0
3 years ago
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