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3 years ago

The height is??? I somehow got the width

Mathematics

2 answers:

Aneli [31]3 years ago

8 0

Answer:

600

Step-by-step explanation:

400=800 not

600/ tama po yan

EleoNora [17]3 years ago

7 0

To find the maximum height, we must find the x value at which the maximum height occurs.

The maximum height occurs at x = 0 because that is where y is the largest.

When we plug x= 0 into the function that is given in the question, we get 630 ft.

Hope it helps!

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Sally paid the following bills rent $450.00 cell phone $37.50 and cable $69.99 how much money did she pay ?

romanna [79]

Answer:

557.49

Step-by-step explanation:

Add the three bills together

450.00

37.50

69.99

--------------

557.49

3 0

3 years ago

((81x^3 y^(-1/3))^1/4)/(x^2 y)^1/4 simplify

malfutka [58]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}
\\\\\\
\left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\
-------------------------------\\\\$

$\bf \cfrac{\left( 81x^3y^{-\frac{1}{3}} \right)^{\frac{1}{4}}}{(x^2y)^{\frac{1}{4}}}\implies \cfrac{81^{\frac{1}{4}}x^{3\cdot {\frac{1}{4}}}y^{-\frac{1}{3}\cdot {\frac{1}{4}}}}{x^{2\cdot {\frac{1}{4}}}y^{\frac{1}{4}}}\implies
\cfrac{81^{\frac{1}{4}}x^{\frac{3}{4}}y^{-\frac{1}{12}}}{x^{\frac{2}{4}} y^{\frac{1}{4}}}$

$\bf \cfrac{81^{\frac{1}{4}}x^{\frac{3}{4}}x^{-\frac{2}{4}}}{ y^{\frac{1}{4}}y^{\frac{1}{12}}}\implies \cfrac{(3^4)^{\frac{1}{4}}x^{\frac{3}{4}-\frac{2}{4}}}{y^{\frac{1}{4}+\frac{1}{12}}}\implies \cfrac{3^{4\cdot \frac{1}{4}}x^{\frac{1}{4}}}{y^{\frac{4}{12}}}\implies \cfrac{3^{\frac{4}{4}}x^{\frac{1}{4}}}{y^{\frac{1}{3}}}
\\\\\\
\cfrac{3\sqrt[4]{x}}{\sqrt[3]{y}}$

7 0

3 years ago

Sam ran 2

daser333 [38]

In total he ran 19 miles based off of how the question looks. It looks like I needed to add each number up.

5 0

3 years ago

The Wind Mountain excavation site in New Mexico is an important archaeological location of the ancient Native American Anasazi c

timurjin [86]

Answer:

a) 28

Class Limits Class Boundaries Midpoint f Rf Cf

10 - 37 9.5-37.5 23.5 7 0.096 7

38 - 65 37.5-65.5 51.5 25 0.342 32

66 - 93 65.5-93.5 79.5 26 0.356 58

94 - 121 93.5-121.5 107.5 9 0.123 67

122 - 149 121.5-149.5 135.5 5 0.068 72

150 - 177 149.5-177.5 163.5 0 0.0 72

178 - 205 177.5-20.5 191.5 1 0.014 73

Total 73 1.0

The histogram is in attached file.

Step-by-step explanation:

The width of class interval=range/desired number of classes

The width of class interval=(maximum-minimum)/7

The width of class interval=(200-10)/7

The width of class interval=190/7

The width of class interval=27.14=28 (rounded to next whole number)

Part(b) and part (c) is explained in attached word document.

Download docx

5 0

3 years ago

Any other answers to this question?

oksano4ka [1.4K]

Answer:

yes the answer is the answer that you need lol thx

hope it helped :)

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers