Answer:
q = -13
Step-by-step explanation:
The given equation is:

Taking 2 as common from left hand side, we get:
![2(x^{2}-4x)=5\\\\2[x^{2} - 2(x)(2)]=5](https://tex.z-dn.net/?f=2%28x%5E%7B2%7D-4x%29%3D5%5C%5C%5C%5C2%5Bx%5E%7B2%7D%20-%202%28x%29%282%29%5D%3D5)
The square of difference is written as:
Equation 1
If we compare the given equation from previous step to formula in Equation 1, we note that we have square of first term(x), twice the product of 1st term(x) and second term(2) and the square of second term(2) is missing. So in order to complete the square we need to add and subtract square of 2 to right hand side. i.e.
![2[x^{2}-2(x)(2)+(2)^2-(2)^{2}]=5\\\\ 2[x^{2}-2(x)(2)+(2)^2]-2(2)^{2}=5\\\\ 2(x-2)^{2}-2(4)=5\\\\ 2(x-2)^2-8=5\\\\ 2(x-2)^{2}-8-5=0\\\\ 2(x-2)^{2}-13=0](https://tex.z-dn.net/?f=2%5Bx%5E%7B2%7D-2%28x%29%282%29%2B%282%29%5E2-%282%29%5E%7B2%7D%5D%3D5%5C%5C%5C%5C%202%5Bx%5E%7B2%7D-2%28x%29%282%29%2B%282%29%5E2%5D-2%282%29%5E%7B2%7D%3D5%5C%5C%5C%5C%202%28x-2%29%5E%7B2%7D-2%284%29%3D5%5C%5C%5C%5C%202%28x-2%29%5E2-8%3D5%5C%5C%5C%5C%202%28x-2%29%5E%7B2%7D-8-5%3D0%5C%5C%5C%5C%202%28x-2%29%5E%7B2%7D-13%3D0)
Comparing the above equation with the given equation:
, we can say:
p = 2 and q= -13
6:3 6 to 3, 9:12 9 to 12 i think that’s what you mean
Take one of the points in the table,
like x=1 y=5
or x=2 y=7
Write them into one of the choices on the list,
and see if the result is true.
For example,
-- Take the line in table that says x=1 y=5.
-- And take the first choice on the list y = x + 3 .
-- Write '1' in place of 'x', and write '5' in place of 'y'.
-- Then you have <u>5 = 1 + 3</u> .
Is this true ? I don't think so.
So the first choice on the list can't be correct.
Try thesame point x=1 y=5 with the other choices.
You'll find one that IS correct, and that's the answer.
Answer:C-2 lines of symmetry