First, factor out a 3.
3(x² - 9)
In any quadratic ax² + bx + c, we can split the bx term up into two new terms which we want to equal the product of a and c.
In this case, we have x² + 0x - 9. (the 0x is a placeholder)
We want two numbers that add to 0 and multiply to get -9.
Obviously, these numbers are 3 and -3.
Now we have 3(x² + 3x - 3x - 9).
Let's factor.
3(x(x+3)-3(x+3))
<u>3(x-3)(x+3)</u>
There are multiple shortcuts which you could make here, FYI:
Instead of splitting the middle, if your a value is 1, you can go straight to that step (x+number)(x+other number).
Whenever you have a difference of squares, like a²-b², that factors to (a+b)(a-b).
I believe that it's A neither, because I don't think that it could be displayed on a coordinate graph when it has an exponent in it. So I think it's A. Let me know if I'm correct. ;-)
Answer:
20.
Step-by-step explanation:
That's the correct answer
Answer:
x=1
Step-by-step explanation:
x = -4 + 6 + (11 + 4(-3)).
First get the numbers in the parentheses
x = -4 + 6 + (11 - 12)
Since 11 - 12 = -1. We can replace (11-12) with -1
x = -4 + 6 -1
Now add and subtract
x = 1
