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liubo4ka [24]
3 years ago
12

cuharra studied Monday and Tuesday for her math test she spent a total of 120 minutes studying. she spend an extra 15 minutes on

Tuesday. how long did she study for on Monday and on tuesday
Mathematics
1 answer:
Mariulka [41]3 years ago
5 0
135? is what i think
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Determine algebraically whether the function is even, odd, or neither even nor odd. f as a function of x is equal to x plus quan
Svetach [21]

y = x + 4/x

replace x with -x. Do you get back the original equation after simplifying. if you do, the function is even. replace y with -y AND x with -x. Do you get back the original equation after simplifying. If you do, the function is odd. A function can be either even or odd but not both. Or it can be neither one. Let's first replace x with -x

y = -x + 4/-x = -x - 4/x = -(x + 4/x)

we see that this function is not the same because the original function has been multiplied by -1 . Let's replace y with -y and x with -x

-y = -x + 4/-x

-y = -x - 4/x

-y = -(x + 4/x)

y = x + 4/x

This is the original equation so the function is odd.

8 0
3 years ago
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Find the volume of the complex figure below.
ikadub [295]
Multiply all the sides
4 0
3 years ago
Read 2 more answers
Which column represents the correct method for the proof of the following statement?
kramer

Answer:

90

Step-by-step explanation:

the colums add up to angle 1, which make angle 2 adjacent.

9-9=0

3 0
3 years ago
Customers arrivals at a checkout counter in a department store per hour have a Poisson distribution with parameter λ = 7. Calcul
IgorLugansk [536]

Answer:

(1)14.9% (2) 2.96% (3) 97.04%

Step-by-step explanation:

Formula for Poisson distribution: P(k) = \frac{\lambda^ke^{-k}}{k!} where k is a number of guests coming in at a particular hour period.

(1) We can substitute k = 7 and \lambda = 7 into the formula:

P(k=7) = \frac{7^7e^{-7}}{7!}

P(k=7) = \frac{823543*0.000911882}{5040} = 0.149 = 14.9\%

(2)To calculate the probability of maximum 2 customers, we can add up the probability of 0, 1, and 2 customers coming in at a random hours

P(k\leq2) = P(k=0)+P(k=1)+P(k=2)

P(k\leq2) = \frac{7^0e^{-7}}{0!} + \frac{7^1e^{-7}}{1!} + \frac{7^2e^{-7}}{2!}

P(k \leq 2) = \frac{0.000911882}{1} + \frac{7*0.000911882}{1} + \frac{49*0.000911882}{2}

P(k\leq2) = 0.000911882+0.006383174+0.022341108 \approx 0.0296=2.96\%

(3) The probability of having at least 3 customers arriving at a random hour would be the probability of having more than 2 customers, which is the invert of probability of having no more than 2 customers. Therefore:

P(k\geq 3) = P(k>2) = 1 - P(k\leq2) = 1 - 0.0296 = 0.9704 = 97.04\%

4 0
3 years ago
Please help me now plz <br> I will mark you brainliest
olga2289 [7]

Answer:

? = 4.28

Step-by-step explanation:

We know that tan theta = opp side / adjacent side

tan 35 = 3 / ?

Multiply each side by ?

? tan 35 = 3

Divide each side by tan 35

? = 3/tan 35

?= 4.28444402

To the nearest hundredth

? = 4.28

5 0
3 years ago
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