<span>2/3 (6e + 9f -21g) -7f
</span><span>2/3 (6e-56f -21g)</span>
Answer: Hello there!
this type of equations in one dimension (when all the factors are constants) are written as:
h = initial position + initial velocity*t + (acceleration/2)*t^2
First, let's describe the hunter's equation:
We know that Graham moves with a velocity of 1.5 ft/s, and when he is 18 ft above the ground, Hunter throws the ball, and because Graham is pulled with a cable, he is not affected by gravity.
If we define t= 0 when Graham is 18 ft above the ground, the equation for Graham height (in feet) is:
h = 18 + 1.5t
where t in seconds.
Now, the equation for the ball:
We know that at t= 0, the ball is thrown from an initial distance of 5ft, with an initial velocity of 24ft/s and is affected by gravity acceleration g, where g is equal to: 32.2 ft/s (notice that the gravity pulls the ball downwards, so it will have a negative sign)
the equation for the ball is:
h = 5 + 24t - (32.2/2)t^2 = 5 + 24t - 16.1t^2
So the system is:
h = 18 + 1.5t
h = 5 +24t - 16.1t^2
so the right answer is A
Answer:
Trinomial
Step-by-step explanation:
This is because there are three terms involved in the equation.
One of them is -7ab^4. Another is 4c^3. The third one is 25.
Answer:
2^3·2^2 = 2^3+2 = 2^5
Step-by-step explanation:
Diego was trying to write 2^3 · 2^2
He wrote 2^3·2^2 = 2^3*2 = 2^6
But this is wrong because when bases are same exponents are added.
This is the law of exponents.
The correct form would be
2^3·2^2 = 2^3+2 = 2^5
For understanding it better we can write it like this
2^3·2^2 =
There are 3 two and 2 twos .When totaled there are 5 two not 6 twos.
It is C..........................Happy Birthday
