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irga5000 [103]
3 years ago
13

What if there are 2 numbers when finding the median

Mathematics
1 answer:
PIT_PIT [208]3 years ago
3 0

add the 2 numbers and then divide by 2

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Derek has $20 to spend on used books. Hardcover books cost $5 each and paperbacks cost $2 each. Complete the equation which dete
nikdorinn [45]

Answer:

The expression would be 5x + 2y = 20

Step-by-step explanation:

We let x be no of hardcover books, and 5x the cost of those books

Same for paperbacks.

then we add them up to 20.

Done!

8 0
3 years ago
6x+4y-3z,7x-11y-9z,14x+8y-6z
Zigmanuir [339]

Step-by-step explanation:

i donot know

sorry about this

8 0
2 years ago
Show that (3+4)2−(3−4)2−(4)(4)=32
tatuchka [14]

Answer:

Explanation below

Step-by-step explanation:

(3+4)= 7

7+2 = 9

-(3-4) (Invisible one)

-3+4 add to the 9

10

10+2= 12

12-4=8

8×4 =32

Sorry if this seems a bit confusing, but its quite hard to show the process without paper.

Hope this helps! :)

8 0
3 years ago
F(13)=45,000(0.9)^13
Nadusha1986 [10]

Answer:

About 879.877

Step-by-step explanation:

To find f,

f(13) = 45,000(0.9)^13

13f = 45,000(0.25418658283)

13f = 11438.3962274

f = 879.877

Please tell me I did this the right way, Thanks!

3 0
3 years ago
two trains leave stations 210 miles apart at the same time and travel tword each other. one train at 85 miles per hour while the
hodyreva [135]

recall your d = rt, distance = rate * time.


let's say we have two trains, A and B, A is going at 85 mph and B at 65 mph.


they are 210 miles apart and moving toward each other, at some point they will meet, when that happens, the faster train A has covered say d miles, and the slower B has covered then the slack from 210 and d, namely 210 - d.


When both trains meet, A has covered more miles than B because A is faster, however the time both have been moving, is the same, say t hours.


\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ \textit{Train A}&d&85&t\\ \textit{Train B}&210-d&65&t \end{array}\\\\ \dotfill\\\\ \begin{cases} \boxed{d}=85t\\ 210-d=65t\\[-0.5em] \hrulefill\\ 210-\boxed{85t}=65t \end{cases} \\\\\\ 210=150t\implies \cfrac{210}{150}=t\implies \cfrac{7}{5}=t\implies \stackrel{\textit{one hour and 24 minutes}}{1\frac{2}{5}=t}

3 0
3 years ago
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