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AlexFokin [52]
3 years ago
10

I’m going to put $100,000 into an investment at the beginning of year 1. At the end of year 2, I am going to add $55,000 more to

the investment. In year 4, I will start to remove $20,000 per year (on the first day of the year). If the interest rate on the investment is 8.2%/year compounded annually, how long (to the nearest year) before the balance in the investment drops to zero? Work this problem on a spreadsheet using simple and compound interest formulas only.

Mathematics
1 answer:
NemiM [27]3 years ago
4 0

Answer:

  19 years

Step-by-step explanation:

The attached spreadsheet shows the balance will be zero at the beginning of year 19, when the last $10,423.27 is withdrawn from the account.

__

One could argue that the "nearest year" is year 18, when the balance after the withdrawal is less than $10,000.

_____

In the attached spreadsheet, the ending balance is 1.082 times the beginning balance (after deposits and withdrawals), which is the ending balance of the year before (after deposits).

In year 1 the beginning balance has 100,000 added. In year 2, the ending balance has 55,000 added. In year 4 and every year after, the beginning balance as 20,000 subtracted.

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Asked on December 20, 2019 by

Ziya Vïvəķ

A cylindrical container with diameter of base 56cm contains sufficient water to submerge a rectangular solid of iron with dimensions (32×22cm×14cm). Find the rise in the level of water when the solid is completely submerged.

MEDIUM

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ANSWER

Given,

Diameter of the base of the cylindrical container d=56 cm

Hence, radius of the base of the cylindrical container r=

2

56

=28 cm

Dimensions of rectangular solid is (32 cm×22 cm×14 cm)

We know that when a body is completely submerged in a container containing water,

the rise in the volume of water in the container is equal to the volume of the body.

Let, the water rises to a height h.

Hence,

Volume of water rises in cylindrical container =Volume of the rectangular solid

πr

2

h=32×22×14 cm

3

7

22

×(28)

2

×h=9856 cm

h=

22×784

9856×7

cm

h=4 cm

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