Difference of 2 perfect squares
a^2-b^2=(a-b)(a+b)
recognize that
(2x+1)(2x-1)
(a+b)(a-b)
therefor
product is
(2x)^2-(1)^2=
4x^2-1
Answer:
True
Step-by-step explanation:
In Prime factorization, we are expected to obtain factors that are prime numbers that can multiply themselves to give the original number. So long as the first factor can divide the number without a remainder, other remaining factors can be multiplied together to give the original number.
Prime factorization of the number, 15 goes thus;
15/3=5
5/5=1
3*5=15
So, all the factors multiply to give the original number.
2.8 = 2 + 0.8
*let's analyze the decimal 0.8 as a fraction
0.8 = 8/10
*but if we divide the numerator and denominator by the same common factor of 2, we find that the fraction can be reduced to:
(8/2)/(10/2) = (4)/(5) = 4/5
*now evaluating the whole value of 2 (from the 2.8), we know there are a total of (5) - fifths in order to make a whole, so for 2 whole, we require:
2*(5/5) = (2*5)/5 = 10/5
*Now we add the fractions together:
2 = 10/5
0.8 = 4/5
10/5 + 4/5
*add numerators only, the denominator stays as a 5
(10 + 4)/5 = 14/5
*there are no common factors between 14 & 5 (other than 1, but that won't help reduce the fraction any), so the fraction is in it's simplest form:
answer is: 14/5
Answer:
1/3
Step-by-step explanation:
Use the Up/to left or right rule to help you
Find a start point (or the one the gave you (3,2)) and then follow the line to the next point that crosses exactly over where to points cross (where poth x and y would be whole numbers) count how many times the point moved up, then how many time it moved left. Put the first over the second in fraction form and there is your slope.
