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3 years ago

Which statement could be used to conclude that this parallelogram is a rhombus?

1 answer:

6 0

A parallelogram is a four-sided shape where the opposite sides are parallel to each other.
A rhombus is a parallelogram with the four sides equal.
Some of the properties of a rhombus are:
1.) All sides are parallel and equal.
2.) Opposite angles are equal
3.) Consecutive angles add up to 180 degrees.
4.) The diagonals bisect the angles.

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Anna's math test grade was 7 points less than her science test grade. The average grade was 91.5%. What did she get on each test

denis23 [38]

Answer:

84.5%

Step-by-step explanation:

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3 years ago

If the surface area of a cube is 294, whats the length of the cube?

tatyana61 [14]

Answer:

Step-by-step explanation:

Total number of surfaces of cube are 6.

Each surface is square.

And area of square is (side)^2

That means, total surface area will be 6 * (side)^2

From question,

294 = 6 * (side)^2 ( Surface area given)

=> 294 ÷ 6 = ( side) ^2

=> 49 = side^2

=> √49 = side

=> 7 = side

So, length of edge of cube is 7

7 0

3 years ago

A tetrahedron is a triangular pyramid with 4 equilateral faces. Han has a box of tetrahedrons with each of the 4 vertices marked

Daniel [21]

Theoretically, the number of the vertex comes at the top must be equal for infinitely many numbers of trials, but it's a tedious job to roll the dice for a large number of times. Rolling the tetrahedron only 10 times will not predict the correct result.

Han suspects that this tetrahedron is weighted in some way to make 1 appear more often than the other numbers.

So, check his suspect experimentally with the help of the concept of center of mass. A fair tetrahedron must have the center of mass at the center of the body.

The given tetrahedron has 4 equilateral triangular faces, so at first, measure all the sides of triangular faces and make sure that all are having the same length.

Then, conduct an experiment to check the location of the center of mass.

Hang the tetrahedron by attaching a thin string at the vertex 1 as shown in the figure and observe the base surface ( triangle 234) whether it is parallel to the ground or not.

Now, repeat the same by hanging it with vertices 2, 3, and 4 and observe the base surface.

For the center of mass to be located at the center of the tetrahedron, the base must be parallel to the ground (flat ground).i.e the hanging string must be perpendicular to the base for all the four cases.

If this is so, then the tetrahedron is a fair tetrahedron otherwise not.

8 0

3 years ago

Need help!! will give brainlist

prisoha [69]

White, 7/10= 14/20
It has the largest chance of being selected at random

5 0

3 years ago

The length of a rectangle is 1 ft less than twice the width, the area of the rectangle is 21 ft squared. What’s the length

guapka [62]

Answer:

The length of the rectangle is 6 feet

Step-by-step explanation:

Given as :

The length of rectangle is 1 feet less than twice the width

So, let The width of rectangle = w feet

The length of rectangle = ( 2 w - 1 ) feet

The area of the rectangle = 21 feet²

Now,

∵ The area of the rectangle = length × width

Or, 21 feet² = ( 2 w - 1 ) feet × w feet

or, 21 = 2 w² - w

or, 2 w² - w - 21 = 0

or, 2 w² + 6 w - 7 w - 21 = 0

or , 2 w ( w + 3 ) - 7 ( w + 3 ) = 0

or, ( w + 3 ) ( 2 w - 7 ) = 0

So, w = - 3 feet , $\frac{7}{2}$ feet

here we consider only positive value of w i.e $\frac{7}{2}$ feet

∴ The length of rectangle = ( 2 w - 1 ) feet

or, The length of rectangle = 2 × $\frac{7}{2}$ - 1

Or, The length of rectangle = 7 - 1 = 6 feet

Hence The length of the rectangle is 6 feet , Answer

3 0

3 years ago