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2 years ago

Which statement could be used to conclude that this parallelogram is a rhombus?

1 answer:

6 0

A parallelogram is a four-sided shape where the opposite sides are parallel to each other.
A rhombus is a parallelogram with the four sides equal.
Some of the properties of a rhombus are:
<span>1.) All sides are parallel and equal.
2.) Opposite angles are equal
3.) Consecutive angles add up to 180 degrees.
4.) <span>The diagonals bisect the angles.</span></span>

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Anyone mind helping!?

Ksju [112]

Answer:

B) $3\sqrt{3}$

Step-by-step explanation:

First simplify the radical on the right.

$\sqrt{75}$ is equal to $\sqrt{25} *\sqrt{3}$ , because 25 * 3 is 75, so we can separate the square roots into the product of these two square roots.

Then we know $\sqrt{25}$ is just equal to 25, which means the simplified version of $\sqrt{75}$ is $5\sqrt{3}$ .

Then we can use this new representation to finish solving.

$8\sqrt{3}-5\sqrt{3} =3\sqrt{3}$ , so the answer would be B

6 0

2 years ago

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I relly need help please please please

madam [21]

Answer:

I think answer is

5.X+11

7 0

3 years ago

If f (x) = x + 7 and g (x) = StartFraction 1 Over x minus 13 EndFraction, what is the domain of (f circle g) (x)?

Rashid [163]

Answer:

R-{13}

Step-by-step explanation:

We are given that

$f(x)=x+7$

$g(x)=\frac{1}{x-13}$

We have to find the domain of fog(x).

$fog(x)=f(g(x))$

$fog(x)=f(\frac{1}{x-13})$

$fog(x)=\frac{1}{x-13}+7=\frac{1+7x-91}{x-13}=\frac{7x-90}{x-13}$

Domain of f(x)=R

Because it is linear function.

Domain of g(x)=R-{13}

Because the g(x) is not defined at x=13

fog(x) is not defined at x=13

Therefore, domain of fog(x)=R-{13}

6 0

2 years ago

Read 2 more answers

(3^2 + 9x + 6) − (8^2 + 3x − 10) + (2x + 4)(3x − 7)

inna [77]

(12+9x) - (6+3x) + 6x + -3
6+3x + 6x+-3
3+ 9x

3 0

3 years ago

A 32 foot tall tree casts a shadow that is 48 feet long. How far away from the tree is a

sveticcg [70]

Answer:

39 feet

Step-by-step explanation:

take the tree as AB , the distance between the man and the tree as BC, the distance between the man and the tip of the shadow CD and the point intersecting the hypotenuse CE

since CE parallel to AB we can BPT

CE/AB = CD/BD

6/32= CD/48

CD = 9 feet

since CD is feet

BC is 48-9 = 39 feet

3 0

1 year ago