Given the graph, find the initial value of the domain [ ___, 2].

Mathematics

1 answer:

Aleks04 [339]2 years ago

5 0

Answer:

Looks to me like it should be -2

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x = 5; the slope is undefined

Step-by-step explanation:

A line perpendicular to the x-axis is a vertical line.

In a vertical line, every point has a different y-coordinate and the same x-coordinate. Since you want a line that is vertical and passes through the point (5, -3), then every point on the line must have x-coordinate 5 no matter what its y-coordinate is. The slope of a vertical line is undefined.

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fiasKO [112]

Hey there!!

Fill in the blanks :-

⇒ First graph the line. Locate the value of x on the x-axis. Draw a vertical line from point plotted on the x-axis to the graph of the function and a horizontal line segment from the graph of the function to the y-axis.

Find the value of f(x) when x is -2.

$f(x) = \frac{3}{2}x-4$

Remember :- f(x) is basically the y-value. It is just denoted as _f(x), it stands for function of x. Which means, the value of y, depends upon the value of x or the function of x.

Given : x = - 2

Plugging in the values :

... $f(-2) = \frac{3*(-2)}{2}-4$