One of the properties of the exponents tells us that when we have a negative exponent we can express it in terms of its positive exponent by turning it into the denominator (and changing its sign), so we would have:

$x^{-3/2}=\frac{1}{x^{3/2} }$

And now, solving for x = 9 we have:

$\frac{1}{x^{3/2}}=\frac{1}{9^{3/2} } =\frac{1}{27}$

b) $y^{4/3}$

This is already a positive rational exponent so we are just going to substitute the value of y = 8 into the expression

$y^{4/3}=8^{4/3}=16$

c) $z^{-3/4}$

Using the same property we used in a) we have:

$z^{-3/4}=\frac{1}{z^{3/4} }$

And now, solving for z = 16 we have:

$\frac{1}{z^3/4} } =\frac{1}{16^{3/4} } =\frac{1}{8}$

4 0

3 years ago

NEED HELP IMMEDIATELY Which expression is equivalent to one over four n − 16?

Gemiola [76]

B. 1/4(n - 64)

Multiplying n and -64 by 1/4 leaves you with 1/4n - 16, the original equation.

5 0

3 years ago

Write the next three terms of the arithmetic sequence.

Inga [223]

Answer:

36, 44, 52

Step-by-step explanation:

Just add 8 to 28 = 36

Add 8 to 36 = 44

Add 8 to 44 = 52

8 0

2 years ago

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