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Andrej [43]
3 years ago
10

Determine the volume occupied by 0.352 mole of a gas at 25⁰C if the pressure is 81.8 kPa.

Chemistry
1 answer:
lions [1.4K]3 years ago
7 0
Data:
p (pressure) = 81.8 kPa = 81.8*10³ Pa ≈ 8.07 atm
v (volume) = ? (in L)
n (number of mols) = 0.352 mol
R (Gas constant) = 0.082 (atm*L/mol*K)
T (temperature) = 25ºC converting to Kelvin, we have:
TK = TC + 273 → TK = 25 + 273 → TK = 298

Formula:
p*V =n*R*T

Solving:
p*V =n*R*T
8.07*V = 0.352*0.082*298
8.07V \approx 8.60
V \approx  \frac{8.60}{8.07}
\boxed{\boxed{V \approx 1.06\:L}}
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Its in the Explanation

Explanation:

Here's what I got.

Aluminium-27 is an isotope of aluminium characterized by the fact that is has a mass number equal to  

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Now, an atom's mass number tells you the total number of protons and of neutrons that atom has in its nucleus. Since you're dealing with an isotope of aluminum, it follows that this atom must have the exact same number of protons in its nucleus.

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