Question

Determine the volume occupied by 0.352 mole of a gas at 25⁰C if the pressure is 81.8 kPa.

Answer 1

Data:
p (pressure) = 81.8 kPa = 81.8*10³ Pa ≈ 8.07 atm
v (volume) = ? (in L)
n (number of mols) = 0.352 mol
R (Gas constant) = 0.082 (atm*L/mol*K)
T (temperature) = 25ºC converting to Kelvin, we have:
TK = TC + 273 → TK = 25 + 273 → TK = 298

Formula:
$p*V =n*R*T$

Solving:
$p*V =n*R*T$
$8.07*V = 0.352*0.082*298$
$8.07V \approx 8.60$
$V \approx \frac{8.60}{8.07}$
$\boxed{\boxed{V \approx 1.06\:L}}$