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3 years ago

The degree to which a liquid resists flowing is called _____.density viscosity conductivity malleability

Chemistry

2 answers:

LUCKY_DIMON [66]3 years ago

5 0

viscosity is the answer that you are looking for

Yuki888 [10]3 years ago

4 0

The degree to which a liquid resists flowing is called viscosity

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Which one of the following is a base?<br>A. HCI <br>B.Cu(OH)2 <br>C.HNO3 <br>D.HC2H3O2

DedPeter [7]

Answer:

b. Cu(OH)2

Explanation:

As it is having Hydroxil ions(OH).

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3 years ago

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if you are using a formula where you need the change in temperature, explain why it is not important whether your temperatures a

alexandr1967 [171]

Answer:

This is because, Kelvins and Celcius degrees both agree at fixed points i.e; the lower fixed point and upper

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3 years ago

If 16.9 kg of Al2O3(s), 57.4 kg of NaOH(l), and 57.4 kg of HF(g) react completely, how many kilograms of cryolite will be produc

hodyreva [135]

Answer: 69.72 kg of cryolite will be produced.

Explanation:

The balanced chemical equation is:

$Al_2O_3(s)+6NaOH(l)+12HF(g)\rightarrow 2Na_3AlF_6+9H_2O$

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

moles of $Al_2O_3$ = $\frac{16.9\times 1000g}{102g/mol}=165.7moles$

moles of $NaOH$ = $\frac{57.4\times 1000g}{40g/mol}=1435moles$

moles of $HF$ = $\frac{57.4\times 1000g}{20g/mol}=2870moles$

As 1 mole of $Al_2O_3$ reacts with 6 moles of $NaOH$

166 moles of $Al_2O_3$ reacts with = $\frac{6}{1}\times 166=996$ moles of $NaOH$

As 1 mole of $Al_2O_3$ reacts with 12 moles of $HF$

166 moles of $Al_2O_3$ reacts with = $\frac{12}{1}\times 166=1992$ moles of $HF$

Thus $Al_2O_3$ is the limiting reagent.

As 1 mole of $Al_2O_3$ produces = 2 moles of cryolite

166 moles of $Al_2O_3$ reacts with = $\frac{2}{1}\times 166=332$ moles of cryolite

Mass of cryolite $(Na_3AlF_6)$ = $moles\times {\text {molar mass}}=332mol\times 210g/mol=69720g=69.72kg$

Thus 69.72 kg of cryolite will be produced.

8 0

3 years ago

Calculate the mass of 488 moles of calcium carbonate

san4es73 [151]

Answer: 48800g

Explanation:

Using the mathematical relation : Moles = Mass / Molar Mass

Moles = 488

Molar mass of CaCO3 = 40 + 12 + (16 x 3) = 100g/mol

Therefore

488 = mass / 100 = 48800g

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3 years ago

Convert 25 liters to millileters and put answer in scientific notation

a_sh-v [17]

1Liter = 1000ml,

Start with the given 25liter X 1000milleters/ 1liters = 25000ml or 2.5X10^4ml

Remember to Cancel the unit...

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3 years ago