The degree to which a liquid resists flowing is called _____.density viscosity conductivity malleability
2 answers:
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Answer:
0.146 M
Explanation:
Equation for the reaction :
2A(aq) ↔ B(aq) + C(aq)
= 65
Molar concentration of A =
= 2.5 M
2A(aq) ↔ B(aq) + C(aq)
Initial 2.50 0 0
Change - 2x + x + x
Equilibrium 2.50 - 2x +x +x
8.062(2.5 - 2x) = x
20.155 - 16.124x = x
20.155 = 16.124x+x
20.155 = 17.124x
x =
x = 1.177
[A] = 2.5 - 2x
= 2.5 - 2(1.177)
= 0.146 M
Therefore, the equilibrium concentration of A = 0.146 M
Answer:
(a)
(b)
(c)
(d)
(e)
Explanation:
Hello,
(a) For the lucite, one computes the moles of C, H and O that are present:
Now, dividing each moles by the smallest moles (oxygen's moles), one obtains:
Finally, we look for the smallest whole number subscript by multiplying by 2, so the empirical formula turns out into:
(b) For the Saran, one computes the moles of C, H and Cl that are present:
Now, dividing each moles by the smallest moles (hydrogen's moles), one obtains:
Finally, as all of the subscripts are whole numbers, the empirical formula turns out into:
(c) For the polyethylene, one computes the moles of C and H that are present:
Now, dividing each moles by the smallest moles (carbon's moles), one obtains:
Finally, as all of the subscripts are whole numbers, the empirical formula turns out into:
(d) For the polystyrene, one computes the moles of C and H that are present:
Now, dividing each moles by the smallest moles (either carbon's or hydrogen's moles), one obtains:
Finally, as all of the subscripts are whole numbers, the empirical formula turns out into:
(e) For the orlon, one computes the moles of C, H and N that are present:
Now, dividing each moles by the smallest moles (nitrogen's moles), one obtains:
Finally, as all of the subscripts are whole numbers, the empirical formula turns out into:
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