The group/family number is the same number of valance electrons.
no it ain’t... period queen
Answer:
168.4 mL
Explanation:
Data Given
initial volume V1 of gas in balloon = 100 mL
initial pressure P1 of gas in balloon = 3.2 atm
final pressure P2 of gas in balloon = 1.9 atm
final volume V2 of gas in balloon = ?
Solution:
This problem will be solved by using Boyle's law equation at constant Temperature.
The formula used
P1V1 = P2V2
As we have to find out Volume, so rearrange the above equation
V2 = P1V1 / P2
Put value from the data given
V2 = 100 mL x 3.2 atm / 1.9 atm
V2 = 168.4 mL
So the final Volume of gas in baloon = 168.4 mL
What makes people wanna come us with these things
We are given with
V = <span>2.394 x 102 mL
P = </span><span>7.20 x 102 mm of Hg
T = </span><span>78 oC
We are asked to determine the mass of the sample in milligrams
Using the ideal gas law
n = PV / RT
n = </span>7.20 x 102 mm of Hg (2.394 x 102 mL) / R (78 + 273)
Use the appropriate value for R or just convert the values to SI and use R = 8.314
Then, solve for the mass of the sample by using the MW Oxygen which is 16 g/mol
