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miskamm [114]
3 years ago
10

The Rockville Recruitment Agency just placed Howard Jacobson in a job as an assistant pharmacist. The job pays $51.2K. The agenc

y fee is equal to 40% of the first three weeks' pay.
c. How much must Howard pay the employment agency to the nearest dollar?
Mathematics
1 answer:
Vitek1552 [10]3 years ago
4 0

Answer:

Step-by-step explanation:

51,200 divided by 52. (52 weeks in a year.) 984.615385 is answer. So each week he gets paid $984.62. So then we multiply that by 3 since we are finding 40% of 3 weeks of pay. $984.62x3= $2953.86. Then we multiply that by 40%.. $2953.86x40%= Answer is $11181.54

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1. Find the distance from point P to QS
12345 [234]

Answer:

5.7 units

Step-by-step explanation:

The distance from point P to QS is the distance from point P (1, 1) to the point of interception R(-3, 5).

Use distance formula to calculate distance between P and R:

PR = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

P (1, 1) = (x_1, y_1)

R(-3, 5) = (x_2, y_2)

Plug in the values into the formula.

PR = \sqrt{(-3 - 1)^2 + (5 - 1)^2}

PR = \sqrt{(-4)^2 + (4)^2}

PR = \sqrt{16 + 16}

PR = \sqrt{32}

PR = 5.7 units (to nearest tenth)

4 0
3 years ago
What is the lengh of a arc wich is a quater of a circle and the adius of that circle is 4,8 cm
Serga [27]

Answer:

eee amiga que quiere decir eso no lo estiendo

5 0
2 years ago
Mary and James each sit in a row of 7 chairs. They choose their seats at random. What is the probability that they don't sit nex
ANTONII [103]

Answer:

2/7

Step-by-step explanation:

theres 7 chairs and 2 people

4 0
2 years ago
The first three terms of an arithmetic series are 6p+2, 4p²-10 and 4p+3 respectively. Find the possible values of p. Calculate t
Doss [256]

Answer:

First Case:

\displaystyle p=\frac{5}{2}\text{ and } d=-2

Second Case:

\displaystyle p=-\frac{5}{4}\text{ and } d=\frac{7}{4}

Step-by-step explanation:

We know that the first three terms of an arithmetic series are:

6p+2, 4p^2-10, \text{ and } 4p+3

Since this is an arithmetic sequence, each subsequent term is <em>d</em> more than the previous term, where <em>d</em> is our common difference.

Therefore, we can write the second term as;

4p^2-10=(6p+2)+d

And, likewise, for the third term:

4p+3=(6p+2)+2d

Let's solve for <em>d</em> for each of the equations.

Subtracting in the first equation yields:

d=4p^2-6p-12

And for the second equation:

2d=-2p+1

To avoid fractions, let's multiply the first equation by 2. Hence:

2d=8p^2-12p-24

Therefore:

8p^2-12p-24=-2p+1

Simplifying yields:

8p^2-10p-25=0

Solve for <em>p</em>. We can factor:

8p^2+10p-20p-25=0

Factor:

2p(4p+5)-5(4p+5)=0

Grouping:

(2p-5)(4p+5)=0

Zero Product Property:

\displaystyle p_1=\frac{5}{2} \text{ or } p_2=-\frac{5}{4}

Then, we can use the second equation to solve for <em>d</em>. So:

2d_1=-2p_1+1

Substituting:

\begin{aligned} 2d_1&=-2(\frac{5}{2})+1 \\ 2d_1&=-5+1 \\ 2d_1&=-4 \\ d_1&=-2\end{aligned}

So, for the first case, <em>p</em> is 5/2 and <em>d</em> is -2.

Likewise, for the second case:

\begin{aligned} 2d_2&=-2(-\frac{5}{4})+1 \\ 2d_2&=\frac{5}{2}+1 \\ 2d_2&=\frac{7}{2} \\ d_2&=\frac{7}{4}\end{aligned}

So, for the second case, <em>p </em>is -5/4, and <em>d</em> is 7/4.

By using the values, we can determine our series.

For Case 1, we will have:

17, 15, 13.

For Case 2, we will have:

-11/2, -15/4, -2.

8 0
2 years ago
Plz Answer 10 points
Lapatulllka [165]

I'll say the first one and the second last one, because the other ones don't make sense to me...

4 0
2 years ago
Read 2 more answers
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