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nikitadnepr [17]
3 years ago
11

Suppose you just received a shipment of twelve televisions. Three of the televisions are defective. If two televisions are rando

mly​ selected, compute the probability that both televisions work. What is the probability at least one of the two televisions does not​ work? The probability that both televisions work is nothing
Mathematics
1 answer:
qwelly [4]3 years ago
6 0

Answer: The probability that both televisions work is 0.5625 .

The probability at least one of the two televisions does not​ work is 0.4375.

Step-by-step explanation:

Given : Number of televisions received in shipment= 12

Number of defective televisions received in shipment= 3

Then proportion of defective televisions =\dfrac{3}{12}=0.25

Using binomial probability formula, the probability of getting success in x trials is given by :-

P(x)=^nC_xp^x(1-p)^{n-x}

If two televisions are randomly​ selected, then the probability that both televisions work will be :-

P(0)=^2C_0(0.25)^0(0.75)^2=(0.75)^2=0.5625

The probability at least one of the two televisions does not​ work will be :-

P(x\geq1)=1-P(0)=1-0.5625=0.4375

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