F(x) = 2^x; h(x) = x^3 + x + 8
Table
x f(x) = 2^x h(x) = x^3 + x + 8
0 2^0 = 1 0 + 0 + 8 = 8
1 2^1 = 2 1^3 + 1 + 8 = 10
2 2^2 = 4 2^3 + 2 + 8 = 8 + 2 + 8 = 18
3 2^3 = 8 3^3 + 3 + 8 = 27 + 3 + 8 = 38
4 2^2 = 16 4^3 + 4 + 8 = 76
10 2^10 = 1024 10^3 +10 + 8 = 1018
9 2^9 = 512 9^3 + 9 + 8 = 729 + 9 + 8 = 746
Answer: an approximate value of 10
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Answer: 0.01
Step-by-step explanation:
Let the events are :
C = paving stones found to be cracked.
D = paving stones found to be discolored.
Given : Total stones : T = 600 (i)
C = 15
D= 27
C'∩D'= 564 (ii)
Since C'∩D' = (C∪D)' = T- C∪D (iii)
From (i) , (ii)and (ii) , we have
564 = 600- C∪D
⇒ C∪D=600- 564= 36
Formula : C∩D= C+D- C∪D
Put values , we get
C∩D= 15+27-36=6
Now ,
The probability that it is both cracked and distorted is 0.01.
7 × 100
+ 0 × 10
+ 6 × 1
0 x 0.1 1/10
+ 3 × 0.01 1/100
+ 9 × 0.001 1/1000
Answer:
Step-by-step explanation:
for f(x):
0
2
2√2
4
for g(x):
2
2√2
2√3
2√5
for h(x):
4
6
4+2√2
8
