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Alisiya [41]
4 years ago
9

The next three terms in the pattern 1, 10, 19, 28, 37 are

Mathematics
2 answers:
konstantin123 [22]4 years ago
8 0
46, 55, 64. It adds by 9 everytime.
Grace [21]4 years ago
7 0
1,10,19,28,37,?,?,?
To find the next three terms, we need to find the patterns in this sequence. In this case, we see that the first number add 9 to get the second number, the second number add 9 to get the third number, and so on. Now, we can create the formula for this which is n+9 where n is the number before the next number. Here we go:
1
1+9=10
10+9=19
19+9=28
28+9=37
37+9=46
46+9=55
55+9=64. As a result, the next three terms in the pattern 1, 10, 19, 28, 37 are 46,55,64. Hope it help!
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Which situation represents the equation: 5x - 18 = 42
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4. Benson sells vacuum cleaners on a commission. He earns $75 for each vacuum cleaner he sells.
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He would have to sell at least 19 vacuums.
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Given: △ACM, m∠C=90°, CP ⊥ AM
larisa86 [58]

Answer:  The answer is 3\dfrac{4}{7}.

Step-by-step explanation:  Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.

Now,

AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)

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5x-1=7x^2-1\\\\\Rightarrow 5x=7x^2\\\\\Rightarrow x=\dfrac{5}{7},~\textup{since }x\neq 0.

Thus,

AM=5\times\dfrac{5}{7}=\dfrac{25}{7}=3\dfrac{4}{7}.

8 0
4 years ago
Write the expression 44(4–7)(4) using a single exponent.
Ghella [55]
<h3>The given expression as single exponent is:</h3>

4^4 \times 4^{-7} \times 4 = 4^{-2}

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

4^4 \times 4^{-7} \times 4

In exponents,

When the base is same, exponents can be added

Which means,

a^m \times a^n = a^{m+n}

Therefore,

4^4 \times 4^{-7} \times 4 = 4^{4-7+1}\\\\Simplify\\\\4^4 \times 4^{-7} \times 4 = 4^{-3+1} \\\\4^4 \times 4^{-7} \times 4 = 4^{-2}

Thus the given expression as single exponent is:

4^4 \times 4^{-7} \times 4 = 4^{-2}

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