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anzhelika [568]
3 years ago
7

Nancy’s 50-meter freestyle swim time was 28.004 seconds. Betty’s 50-meter freestyle swim time was 27.949 seconds. What was the d

ifference between Nancy’s and Betty’s swim times?
Mathematics
2 answers:
vladimir2022 [97]3 years ago
8 0
If you subtract Betty's time for the swim, 27.948 seconds, from Nancy's time, 28.004 seconds, you will find that Betty was faster than Nancy by 0.056 seconds. She would be considered the winner of the 50-meter freestyle swim.
Vladimir [108]3 years ago
3 0

Answer:

Difference between Nancy's and Betty's swim times will be 0.055 seconds.

Step-by-step explanation:

It is given in the question that Nancy's 50- meter freestyle swim time was 28.004 sec. and Betty's swim time was 27.949 sec.

We have to calculate the difference between their swim times.

So to find difference from Nancy's swim time and Betty's swim time we will subtract Betty's swim time from Nancy's time.

The difference will be = 28.004 - 27.949 = 0.055 sec.

And the winner is Betty who took 0.055 seconds lesser than Nancy's swim time.

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Step-by-step explanation:

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2. Add the product obtained and the numerator of the fraction (This will be the new numerator).

3. The denominator does not change.

Then:

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You know that he had 30 minutes in time-out, he counted spots on the ceiling for \frac{70}{3} minutes and the rest of the time he made faces at his stuffed tiger.

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Step-by-step explanation:

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Answer:

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