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ira [324]
3 years ago
14

A population of 6000 animals decrease at an annual rate of 0.7%. What is the expected population in 12 years? Round your answer

to the nearest whole number.
Mathematics
1 answer:
solmaris [256]3 years ago
6 0

Answer:

The population is expected to be 5515 animals in 12 years.

Step-by-step explanation:

This problem can be solved by using a compounded interest formula with a negative interest rate, since the number of animals are decreasing. We have:

final population = initial population * (1 - r)^(t)

Where r is rate of decline and t is the time elapsed. Applying the data from the question we have:

final population = 6000*(1 - 0.007)^(12)

final population = 6000*(0.993)^12 = 5514.9582 animals

The population is expected to be 5515 animals in 12 years.

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Answer:

6x - 5y = -5

Step-by-step explanation:

Your FIRST goal is to fill out y = mx + b with the values of m (your slope) and b (your y-intercept). First, find m by dividing the change in y in the two points given by their change in x. (43 - 31)/(35-25) = 12/10 = 6/5. Plug this in immediately for a "placeholder equation" of y = 6/5x + b, which you can plug either of your points into and solve for b.

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Your SLOPE-INTERCEPT equation is y = 6/5x + 1. However, you were asked for standard form. This means you must convert into ax + by = c, where a b and c are all whole numbers, and a is positive.

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Let me know if you need a more in-depth explanation on any part of this!

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Alenkasestr [34]

; Simplified =

Let "Zoe" = z

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