Hi there!
To create an expression that uses the distribution property which can be simplified into 40 + 4x, we can find a factor between 40 and 4:
Since both 40 and 4 is divisible by 4,
40 / 4 = 10
4 / 4 = 1
We can put the 4 on the outside of the parenthesis, and put the quotients inside the parenthesis. And since the expression is in addition, we should include the addition symbol as the operation inside the parenthesis.
4(10 + x)
would be your answer.
Hope this helps!
Answer:
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
Answer:
B
Step by Step explanation:
So since the equation says that 8 is less than the square root for b, It is correct because the square root of 72 would be 8.48528137424. Which of course 8, is less than that. But it also says that the square root of 72 is less than 9. Which based on my calculations would be correct.
Answer:
1
Step-by-step explanation:
using PEDMAS(parentheses, exponents, division, multiply, addition, subtraction) to solve the problem
First we multiply (4)(-3)
(4)(−3)−5−3(−6)
Then multiply -3(-6)
(-12)-5-3(-6)
=-12-5+18
subtract 12-5
-12-5+18
=-17+18
Adding -17+18 gives us 1.
Therefore, (4)(−3)−5−3(−6) is 1.
In a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs (A) at a0. the first Bohr radius.
<h3>
What is an electron?</h3>
- The electron is a subatomic particle with a negative one elementary charge electric charge.
- Electrons are the first generation of the lepton particle family and are widely regarded as elementary particles due to the lack of known components or substructure.
Electron in the hydrogen:
- Hydrogen has the simplest electron configuration to write because it just contains one electron.
- There is essentially only one electron surrounding the Hydrogen nucleus.
- Because hydrogen only has one electron, its configuration is 1s1.
- The maximum occurs at a0, the first Bohr radius, in a plot showing the chance of finding the electron in the hydrogen ground state vs the distance from the nucleus.
Therefore, in a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs (A) at a0. the first Bohr radius.
Know more about electrons here:
brainly.com/question/860094
#SPJ4
The complete question is given below:
In a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs:
A. at a0. the first Bohr radius
B. at slightly less than a0
C. at slightly more than a0
D. at 2 a0
E. at a0/2
