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tankabanditka [31]
3 years ago
11

30 points What is the opposite of cosine called and what is its triangle ratio

Mathematics
1 answer:
Liula [17]3 years ago
7 0

Answer: Answer is below

Step-by-step explanation: The answer is that the opposite of a cosine is called a hypotenuse. The ratio of the triangle is called a tangent.

I hope this info helps! :V

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the sides of a triangle are 3 whole 1 by 6 cm 4 whole 2 by 3 cm and 5 whole 2 by 3 cm. Find the total length of the three sides
Lyrx [107]

Answer:

16\frac{2}{3}cm

Step-by-step explanation:

Given dimensions:

           3\frac{1}{6} cm by 4\frac{2}{3}cm  by 5\frac{2}{3} cm

The total length:

 it is the sum of all the sides;

         \frac{19}{6}  + \frac{14}{3}   + \frac{17}{3}  

LCM of the denominators = 6 ;

   \frac{38 + 28 + 34}{6}  = \frac{100}{6}

                 = \frac{50}{3}

                 = 16\frac{2}{3}cm

5 0
3 years ago
Can someone explain how to get the answer,<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B105%7D%7B2%7D%20" id="TexFormula1"
krek1111 [17]
\bf \cfrac{x}{5}-\cfrac{x}{7}=3\impliedby &#10;\begin{array}{llll}&#10;\textit{let's multiply both sides by }\stackrel{LCD}{35}\\&#10;\textit{to do away with the denominators}&#10;\end{array}&#10;\\\\\\&#10;35\left( \cfrac{x}{5}-\cfrac{x}{7}\right)=35(3)\implies 7x-5x=105&#10;\\\\\\&#10;2x=105\implies x=\cfrac{105}{2}
4 0
2 years ago
Read 2 more answers
Let T : V → W be a linear transformation from vector space V into vector space W.
wel

Explanation:

Since {v1,...,vp} is linearly dependent, there exist scalars a1,...,ap, with not all of them being 0 such that a1v1+a2v2+...+apvp = 0. Using the linearity of T we have that

a1*T(v1)+a2*T(v1) + ... + ap*T(vp) = T(a1v19+T(a2v2)+...+T(avp) = T(a1v1+a2v2+...+apvp) = T(0) = 0.

Since at least one ai is different from 0, we obtain a non trivial linear combination that eliminates T(v1) , ..., T(vp). That proves that {T(v1) , ..., T(vp)} is a linearly dependent set of W.

7 0
3 years ago
The measure ∠BQS of is 80°. What is the m∠NQS? 42° 48° 128° 32°
fomenos

Answer:

m<NQS = 32°

Step-by-step explanation:

Given:

m<BQS = 80°

m<BQN = 48°

Required:

m<NQS

SOLUTION:

Angle BQN and angle NQS are adjacent angles having a common line, QN, and a common corner point, Q.

Therefore:

m<BQN + m<NQS = m<BQS (angle addition postulate)

48° + m<NQS = 80° (substitution)

m<NQS = 80 - 48° (Subtraction of 48 from each side)

m<NQS = 32°

3 0
3 years ago
Read 2 more answers
A _______________________ is a comparison of two measurements in which the denominator has a value of one unit.
Galina-37 [17]
I think the answer is unit rate.
8 0
3 years ago
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