We have that
x²<span>-6x+7=0
</span>Group terms that contain the same variable
(x²-6x)+7=0
Complete the square Remember to balance the equation
(x²-6x+9-9)+7=0
Rewrite as perfect squares
(x-3)²+7-9=0
(x-3)²-2=0
(x-3)²=2
(x-3)=(+/-)√2
x=(+/-)√2+3
the solutions are
x=√2+3
x=-√2+3
Answer:
10.6
Step-by-step explanation:
-2.2 is 2.2 units away from zero and 8.4 is 8.4 away from zero on a number line. add 2.2 and 8.4
Once you have the points they make a 3-4-5 triangle. The two legs are 3 and 4, so the hypotenuse has to be 5. Or you could use the pythagorean theorem a² + b² = c² 3² + 4² = c² 25 = c² c = 5
then find area
A=1/2bh
1/2(3*4)
6
Yes,because that is $3.03 higher than what he is receving right now so that will be an accelent option:)