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3 years ago

A) -5x2 + 2x - 2 = 0

1 answer:

6 0

I believe you wanted that solved? My math is down below.-

1. You have the equation, which is -5•2+2x-2=0.

2. Multiply -5•2 = -10.

3. Then, you get::-10+2x-2=0.

4. Combine the like-terms:
| -10 - -2 = -8. |

5. Combine this with the original equation.

6. -8 + 2x = 0
- 8 - 8
————————
2x. = 8
———- ——
2 2

x= 4

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Whats the value of 1/6^0? 1/6 0 1

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Answer:

1 (anything with the exponent of 0 always equals 1)

Step-by-step explanation:

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2 years ago

Which statements are true about the circle shown? Check all that apply.

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Step-by-step explanation:

A circle is only composed of the points on the border
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3 years ago

PLEASE HELP WILL GIVE BRAINLIEST

Marta_Voda [28]

Answer:

The bird will have traveled 403 meters in 13 seconds if it maintained a speed of 31 m/sec

Explanation:

The equation that relates velocity, distance and time is:

$velocity = \frac{distance}{time}$

This means that:

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In the given, we have:

velocity = 31 m/sec

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2 years ago

*ANSWER PLS TY* Find The Volume Of The Pyramid

spin [16.1K]

Answer: A. 1120 in³

Step-by-step explanation:

the formula for the volume of the pyramid: $V=\frac{1}{3} lwh$

l (length)=16

w (width)=14

h (height)=15

$V=\frac{1}{3} lwh$

$V=\frac{1}{3} (16)(14)(15)$

$V=\frac{1}{3} 3360$

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3 0

3 years ago

Read 2 more answers

I need help with 20, 23-25 please

Doss [256]

Step-by-step answer:

All the problems use absolute value function |x|

|x| means the positive value of x. That means |x| = |-x|

For example, |23| = |-23| = 23 (positive value)

In solving linear equations with absolute value functions, we generally have two solutions, for example:

|x+1| =7 mean we solve for x in

(x+1) = 7 => x=6, (when x+1 >0)

-(x+1) = 7 => x=-8 (when x+1<0)

So the solution is x=6 or x=-9

Q20:

Given: a=-2, b=-3, c=2, x=2.1, y=3, z=-4.2

Evaluate -3|z| + 2 (a + y)

Solution:

Substitute values, namely

-3|z| + 2 (a + y)

= -3 |-4.2|

In solving linear equations with absolute value functions, we generally have two solutions, for example:

|x+1| =7 mean we solve for x in

(x+1) = 7 => x=6, (when x+1 >0)

-(x+1) = 7 => x=-8 (when x+1<0)

So the solution is x=6 or x=-9

Q23:

|f+10|=1

when f+10 > 0 : (f+10) = 1 => f+10 = 1 => f = 1 - 10 => f = -9

when f+10 < 0 : -(f+10) = 1 => -f -10 = 1 => -f = 1+10 => -f = 11 => f = -11

The solution is therefore f = { -9, -11 }

Q24:

| v-2 | = -5

when v-2 > 0 : (v-2) = -5 => v-2 = -5 => v=-5+2 => v = -3

when v-2 < 0 : -(v-2) = -5 => -v +2 = -5 => -v = -5-2 => v = 7

The solution is therefore v = {-3, 7}

Q25:

| 4t-8 | = 20

when 4t-8 > 0 : (4t-8) = 20 => 4t = 20+8 => 4t=28 => t=7

when 4t-8 < 0 : -(4t-8) = 20 => -4t +8 = 20 => -4t = 20-8 => -4t = 12 => t = -3

The solution is therefore t = { 7, -3 }

6 0

2 years ago