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Nimfa-mama [501]
3 years ago
13

Which best describes the slope of the given line?

Mathematics
1 answer:
statuscvo [17]3 years ago
8 0

Answer:  The slope = 0

Step-by-step explanation:

You might be interested in
SERIOUS ANSWERS ONLY PLZ
statuscvo [17]

Answer:

<u>The standard deviation of the uniform distribution is:</u>

  • σ=(b−a)/√12

<u>U(3, 12)</u>

  • σ = (12−3)/√12 = 9/√12 = 2.5981

<u>U(80, 250)</u>

  • σ = (250−80)/√12 = 170/√12 = 49.0748

<u>U(4, 93)</u>

  • σ = (93−4)/√12 = 89/√12 = 25.6921

5 0
3 years ago
Parallel / Perpendicular Practice
deff fn [24]

The slope and intercept form is the form of the straight line equation that includes the value of the slope of the line

  1. Neither
  2. ║
  3. Neither
  4. ⊥
  5. ║
  6. Neither
  7. Neither
  8. Neither

Reason:

The slope and intercept form is the form y = m·x + c

Where;

m = The slope

Two equations are parallel if their slopes are equal

Two equations are perpendicular if the relationship between their slopes, m₁, and m₂ are; m_1 = -\dfrac{1}{m_2}

1. The given equations are in the slope and intercept form

\ y = 3 \cdot x + 1

The slope, m₁ = 3

y = \dfrac{1}{3} \cdot x + 1

The slope, m₂ = \dfrac{1}{3}

Therefore, the equations are <u>neither</u> parallel or perpendicular

  • Neither

2. y = 5·x - 3

10·x - 2·y = 7

The second equation can be rewritten in the slope and intercept form as follows;

y = 5 \cdot x -\dfrac{7}{2}

Therefore, the two equations are <u>parallel</u>

  • ║

3. The given equations are;

-2·x - 4·y = -8

-2·x + 4·y = -8

The given equations in slope and intercept form are;

y = 2 -\dfrac{1}{2}  \cdot x

Slope, m₁ = -\dfrac{1}{2}

y = \dfrac{1}{2}  \cdot x - 2

Slope, m₂ = \dfrac{1}{2}

The slopes

Therefore, m₁ ≠ m₂

m_1 \neq -\dfrac{1}{m_2}

The lines are <u>Neither</u> parallel nor perpendicular

  • <u>Neither</u>

4. The given equations are;

2·y - x = 2

y = \dfrac{1}{2} \cdot   x +1

m₁ = \dfrac{1}{2}

y = -2·x + 4

m₂ = -2

Therefore;

m_1 \neq -\dfrac{1}{m_2}

Therefore, the lines are <u>perpendicular</u>

  • ⊥

5. The given equations are;

4·y = 3·x + 12

-3·x + 4·y = 2

Which gives;

First equation, y = \dfrac{3}{4} \cdot x + 3

Second equation, y = \dfrac{3}{4} \cdot x + \dfrac{1}{2}

Therefore, m₁ = m₂, the lines are <u>parallel</u>

  • ║

6. The given equations are;

8·x - 4·y = 16

Which gives; y = 2·x - 4

5·y - 10 = 3, therefore, y = \dfrac{13}{5}

Therefore, the two equations are <u>neither</u> parallel nor perpendicular

  • <u>Neither</u>

7. The equations are;

2·x + 6·y = -3

Which gives y = -\dfrac{1}{3} \cdot x - \dfrac{1}{2}

12·y = 4·x + 20

Which gives

y = \dfrac{1}{3} \cdot x + \dfrac{5}{3}

m₁ ≠ m₂

m_1 \neq -\dfrac{1}{m_2}

  • <u>Neither</u>

8. 2·x - 5·y = -3

Which gives; y = \dfrac{2}{5} \cdot x +\dfrac{3}{5}

5·x + 27 = 6

x = -\dfrac{21}{5}

  • Therefore, the slopes are not equal, or perpendicular, the correct option is <u>Neither</u>

Learn more here:

brainly.com/question/16732089

6 0
3 years ago
Just answer the multiple-choice pls
Yanka [14]

Answer:

its B

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Solve: -3= 12x-5(2x-7)
leonid [27]

Answer:

x = -19

Step-by-step explanation:

-3= 12x-5(2x-7)

Distribute

-3= 12x-10x+35

Combine like terms

-3 = 2x +35

Subtract 35 from each side

-3-35 = 2x+35-35

-38 = 2x

Divide each side by 2

-38/2 = 2x/2

-19 =x

7 0
3 years ago
Solve equation 3x-5y=7 5x-2y=-1 by elimination
kakasveta [241]

Answer:

x = -1, y = -2.

Step-by-step explanation:

Using the elimination method,

multiply the first eqn by 2 and the 2nd eqn by 5.

6x - 10y = 14

25x - 10y = -5

Subtract one of the new equations from the other

-19x = 19

x = -1

Sub x=-1 into the 2nd eqn

-5 - 2y = -1

y = -2

Hence x = -1, y = -2.

7 0
3 years ago
Read 2 more answers
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