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zzz [600]
3 years ago
7

Julie needs to cut 4 pieces of yarn, each with the same length, and a piece of yarn 7.75 inches long. Let x represent the length

of each of the equal pieces of yarn that Julie decides to cut. What is the equation that can be used to determine the total length of all of the yarn that she ends up cutting, y? Is the graph of the equation continuous or discrete?
Mathematics
2 answers:
Lera25 [3.4K]3 years ago
6 0
7.75/4 = x
It is discrete...
Pavlova-9 [17]3 years ago
5 0
Hi!

The answer would be: D). y=4x+7.75; continuous. Let me know if this is right!
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The volume of a sphere is 5000 pi m 3 what is the surface area
Nikitich [7]
V = \frac{4}{3}\pi r^3
\\ 5000\pi = \frac{4}{3} \pi r^3
\\ 5000 = \frac{4}{3} r^3
\\ \frac{3}{4} * 5000 = r^3
\\ 3750 = r^3
\\ r = 15.536
\\ SA = 4 \pi r^2
\\ SA = 4\pi (15.536)^2
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8 0
3 years ago
Shane and Abha earned a team badge that required their team to collect no less than 2000 cans for recycling. Abha collected178 m
Agata [3.3K]

Answer:

Let number of cans collected by Shane =S

Number of cans collected by Abha=S+178

As, it is given that ,Abha collected 178 more cans than Shane did.

Also, the statement about inequality is

Both Shane and Abha have to collect no less than 2000 cans for recycling.

Writing the statement in terms of inequality

S +S+178 ≥ 2000

2 S ≥ 2000 - 178

2 S ≥ 1822

Dividing both sides by 2, we get

S≥ 911

So, Shane must have collected At least 911 cans.

6 0
3 years ago
Read 2 more answers
Can I please get some help with both problems
dimulka [17.4K]
So you subtract 180 from 90 you get you answer then you will divide it by 55 and your remaining answer which you will get will be x 
4 0
3 years ago
Based on the graph which of the following statements are true
Gre4nikov [31]

you can't really see the question it's too blurry

4 0
3 years ago
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Click on the measure of angle x.<br> х<br> 38°<br> » 152<br> 1)) 142°<br> () 38°<br> )) 52°
GaryK [48]

Answer:

142°

Step-by-step explanation:

180^{\circ} - 38^{\circ} = 142^{\circ}

7 0
3 years ago
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