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iragen [17]
3 years ago
11

I need help please help

Mathematics
1 answer:
timurjin [86]3 years ago
3 0
What is this nonsense math ? What kind of teacher would give this math
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Find the exact circumference of a circle with the given radius 3 and 1/2 cm​
Marina86 [1]

Answer:

Step-by-step explanation:

Radius is half diameter so you have to multiply the radius by 2 to find diameter.

3 1/2 * 2 = 7

7 0
3 years ago
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Through what angle does the minute hand of a clock turn in 12 minutes of time?
harina [27]
A method to solve such problems is to consider the rate of change of the angle in degrees per minute. The hour hand of a normal 12-hour analogue clock turns 360° in 12 hours (720 minutes) or 0.5° per minute. The minute hand rotates through 360° in 60 minutes or 6° per minute.
6 0
4 years ago
A right rectangular prism has a volume of 120 in. What is the new volume if the length, width and height are doubled?
hjlf
We don't know what the dimensions are, but any numbers that have a sum of 120 will work. Let's use 3, 4, and 10.

3 x 4 = 12   10 x 12 = 120

But if you double each dimension:

6 x 8 = 48     48 x 20 = 960         To find how much the sums changed:

960 / 120 = 8     

The new volume is 8 times what it originally was! 960 in.
7 0
3 years ago
Pleasseee help me with this.it’s life or death
barxatty [35]

Answer:

(a) 4 miles

(b) 8.9 miles

Step-by-step explanation:

(a) Theorem 1: In a right triangle, the altitude drawn from the right angle to the hypotenuse divides the hypotenuse into two segments. The length of the altitude is the geometric mean of these two segments.

Hence, the distance d between the park and the library is

d^2=2\cdot 8\\ \\d^2=16\\ \\d=4\ miles

(b) Theorem 2: In a right triangle, the altitude drawn from the right angle to the hypotenuse divides the hypotenuse into two segments. The length of each leg of the right triangle is the geometric mean of the lengths of the hypotenuse and the segment of the hypotenuse that is adjacent to the leg.

Thus, the distance D between the park and the football field is

D^2=8\cdot (2+8)\\ \\D^2=8\cdot 10\\ \\D^2=80\\ \\D=\sqrt{80}=4\sqrt{5}\approx 8.9\ miles

4 0
3 years ago
The distribution of a sample of the outside diameters of PVC pipes approximates a normal distribution. The mean is 14.0 inches,
lakkis [162]

Answer:

A. 13.9 and 14.1 inches

See explanation below.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the outside diameters of a population, and for this case we know the distribution for X is given by:

X \sim N(14,0.1)  

Where \mu=14 and \sigma=0.1

If we want the middle 68% of the data we need to have on the tails 16% on each one

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.84   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.16 of the area on the left and 0.84 of the area on the right it's z=-0.994. On this case P(Z<-0.994)=0.16 and P(z>-0.994)=0.84

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-0.994

And if we solve for a we got

a=14 -0.994*0.1=13.9

And since the distribution is symmetrical for the upper limit we can use z = 0.994 and we have:

z=0.994

And if we solve for a we got

a=14 +0.994*0.1=14.1

So the correct answer for this case would be:

A. 13.9 and 14.1 inches

3 0
4 years ago
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